Optimization of a nested loop
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Hello guys I wrote the following code, but it takes ages to complete. Could you please help me optimizing it? A and B are matrixes
for i=1:length(A)
for j=1:length(B)
CCI = CCI + heaviside(norm(A(i,:)-B(j,:)));
end
end
Thanks
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回答(2 个)
Sean de Wolski
2012-6-22
Not necessarily faster, prettier, less confusing or better in any way with the exception of being on one line and containing the awesomeness that is bsxfun:
CCI2 = sum(sum(heaviside(sqrt(sum(bsxfun(@minus,A,reshape(B',1,size(B,2),size(B,1))).^2,2)))))
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Andrei Bobrov
2012-6-22
other variant
CCI = (nnz(any(bsxfun(@minus,A,reshape(B',1,size(B,2),[])),2)) + size(A,1)*size(B,1))/2;
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