how to plot by scatter3 a 3D matrix with its elements being logic variables?

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Woo-Seok Lee 2018-9-12

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评论： jonas 2018-11-18

I made a 3D matrix representing a ellipsoid. The elements are logic variables, 1 or NaN. I thought this 3D matrix as Cartesian coordinate and the points on it. I want to plot this by using scatter3. But scatter3 accepts 1D vectors as inputs for position. (Before, I made a 2D matrix representing a ellipsoid and plotted this by using imagesc. This function accepts 2D matrix and don't require position vectors.)

Here is the code.

%making a coordinate
Sx=1; Sy=1; Sz=1; Nx=50; Ny=50; Nz=50; dx= Sx/Nx; dy=Sy/Ny; dz=Sz/Nz;
xa=[0:Nx-1]*dx;
ya=[0:Ny-1]*dy;
za=[0:Nz-1]*dz;
xa=xa-mean(xa);
ya=ya-mean(ya);
za=za-mean(za);
[X,Y,Z]=meshgrid(xa,ya,za);
%ellipsoid
rx=0.5;
ry=0.35;
rz=0.2;
A=zeros(length(xa),length(ya),length(za));
A(((X/rx).^2+(Y/ry).^2+(Z/rz).^2)<=1)=1; 
A(((X/rx).^2+(Y/ry).^2+(Z/rz).^2)>1)=NaN;

Now I don't know how to transform the matrix for scatter3

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采纳的回答

jonas 2018-9-12

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编辑：jonas 2018-9-12

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You can use your logic data in A to set the color and your X, Y and Z data for coordinates.

scatter3(X(:),Y(:),Z(:),[],A(:))

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Valeriy 2018-11-18

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I try tor reproduce command set(h1,'markeredgealpha',0.05),

but I have obtained message:

Error using specgraph.scattergroup/set
The name 'markeredgealpha' is not an accessible property for an instance
of class 'scattergroup'.

Help for scattergroup properties don't show presence of "markeredgealpha". How it works?

jonas 2018-11-18

在 MATLAB Online 中打开

You probably have to specify that already when plotting, i.e.:

scatter(..., 'markeredgealpha',0.05)

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