How can I split a matrix into N different parts?

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Mete Naz 2018-9-12

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评论： ANKUR KUMAR 2018-9-13

Hey Guys, I have a matrix X (80,160), and I want to divide it in to 18 regions. You can find the regions specifications in the picture. I could divide them into 18 almost equal parts but that is not what I need.I actually could not figure out how to divide it into those kind of regions. I would appreciate if anybody can help. Thanks

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jonas 2018-9-12

编辑：jonas 2018-9-12

What do you mean divide them? How do you want to store each part? Hint: an array must be rectangular.

Mete Naz 2018-9-12

I want to store them as sub matrices basically. If you look at the picture you will see how I want to divide them into 18 parts

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Answer 1

ANKUR KUMAR 2018-9-12

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编辑：ANKUR KUMAR 2018-9-12

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Firstly change data into polar coordinates, so that your complete data will change into angles and radius. After conversion, your data will be of dimension (360 [angles]* 100 [assumed as radius]) After this, you can easily crop data as your wish (as mentioned in your image).

You conversion will somewhat looks like

[xx,yy]=pol2cart(angle,radius);
z=interp2(lon,lat,data,xx,yy);

where 'lon', 'lat' is the x and y coordinates of your rectangular dataset ('data')

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Mete Naz 2018-9-12

I have converted the data into polar coordinates. I am kind of new on matlab so I do not know How I am supposed to easily crop my data as shown in the picture? I would appreciate your help!

ANKUR KUMAR 2018-9-13

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After conversion into polar, your data will be in dimension of 360 * 100 (assuming angular resolution is 1 degree and radius has 100 units). As per your figure, suppose 1st part is around 60 to 120 degree and radius may be 66 to 100 units. Then simply do

A_cropped=A(60:120,66:100);

where A is the polar converted matrix.

The only hurdle in your problem is conversion. Once you are done with the conversion, it's very easy to crop the data as per your figure.

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