Help with my fibonacci sequence code
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0, 1, 1, 2, 3, 5, 8, 13, 21, 34, ... (add previous two numbers together for the next in the sequence)
1. Use a for-end statement to find the 100th number in the sequence.
2. Update this script using a while statement to find the first number in the sequence that has six digits.
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This is my code until now.
% fibonacci
a=0; b=1; n=input('Enter no, of terms: ');
for i=1:n fprintf('%d',a); fprintf('\t') c=a+b; a=b; b=c;
end
I'm not sure if is correct. But the assignment require to find the 100th number with a for-end and the other part is to find the sequence that has six digits.
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John D'Errico
2023-1-26
@Abhishek - actually, it is not correct. It does not solve the assignment. And while it does appear to compute Fibonacci numbers, the code does not do what was required.
采纳的回答
Jim Riggs
2018-9-12
编辑:Jim Riggs
2018-9-12
This is how I did it. This function will give the nth number in the Fibonacci sequence:
function f=fib(n)
s=[1, 1];
if n>2
for i=3:n
s(i) = s(i-1)+s(i-2)
end
end
f = s(n)
end
The number of digits in a number, n, is
floor(log10(n))+1
so you can write a loop:
n=1;
nd=1;
while nd < 6
n=n+1
fn = fib(n)
nd = floor(log10(fn))+1;
end
When this loop ends, fn is the first Fibonacci number with 6 digits, and it is the nth in the sequence.
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