Help with my fibonacci sequence code
显示 更早的评论
0, 1, 1, 2, 3, 5, 8, 13, 21, 34, ... (add previous two numbers together for the next in the sequence)
1. Use a for-end statement to find the 100th number in the sequence.
2. Update this script using a while statement to find the first number in the sequence that has six digits.
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This is my code until now.
% fibonacci
a=0; b=1; n=input('Enter no, of terms: ');
for i=1:n fprintf('%d',a); fprintf('\t') c=a+b; a=b; b=c;
end
I'm not sure if is correct. But the assignment require to find the 100th number with a for-end and the other part is to find the sequence that has six digits.
2 个评论
Abhishek
2023-1-26
it is correct
John D'Errico
2023-1-26
@Abhishek - actually, it is not correct. It does not solve the assignment. And while it does appear to compute Fibonacci numbers, the code does not do what was required.
采纳的回答
This is how I did it. This function will give the nth number in the Fibonacci sequence:
function f=fib(n)
s=[1, 1];
if n>2
for i=3:n
s(i) = s(i-1)+s(i-2)
end
end
f = s(n)
end
The number of digits in a number, n, is
floor(log10(n))+1
so you can write a loop:
n=1;
nd=1;
while nd < 6
n=n+1
fn = fib(n)
nd = floor(log10(fn))+1;
end
When this loop ends, fn is the first Fibonacci number with 6 digits, and it is the nth in the sequence.
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