Count two columns with corresponding data

5 次查看(过去 30 天)
Hey guys! So im having a question regarding counting things in matlab. I have a Matrix with one column of direction and one column of the speed So what i want to do is to find all data that has lets say a direction between 0-45degrees and a speed of 0<x<3 And then i want to count how many there are. Why I cant do it by hand is because its a large sheet of data. I guess we want to use some if statements like if 0<direction<45 & 0<speed<3 . . . But I dont know how to write it. Hope u get what i mean, thanks!

采纳的回答

jonas
jonas 2018-9-13
编辑:jonas 2018-9-13
Try this:
x is speed, y is direction
sum(x>0 & x<3 & y>0 & y<45)
the conditions inside of the braces gives a logical array which yields true (1) when satisfied and otherwise false (0).
EDIT: removed brackets
  6 个评论
Guillaume
Guillaume 2018-9-13
We would say -45 to 45 degrees, but the data is only in 0 to 360
It's a simple matter of shifting to [-180:180]
direction = mod(direction + 180, 360) - 180; %shift 0:360 to -180:180 range
count = nnz(speed > 0 & speed < 3 & direction > -45 & direction < 45)
Or you keep your 0:360 range and adapt your comparison (which needs splitting in two ranges, 0-45 and 315-360)
count = nnz(speed > 0 & speed < 3 & ((direction > 0 & direction < 45) | (direction > 315 & direction < 360)))
Note that you may want to change some of these > and < into >= and <=.
Joakim Karlsson
Joakim Karlsson 2018-9-13
Thanks guys I will probably solve it now with your help!

请先登录,再进行评论。

更多回答(1 个)

Aquatris
Aquatris 2018-9-13
编辑:Aquatris 2018-9-13
One thing you can do is (assuming you have newer versions of matlab);
A = rand(10,2); % the data
a1 = A(A(:,1)<0.3,:); % find rows where 1st column is less than 0.3 in data
a2 = a1(a1(:,2)>0.9,:); % find rows where 2nd column is greater than 0.9 in a1
n = size(a2,1); % number of rows of data where 1st colum is less than 0.3 and 2nd
% column is greater than 0.9
If you have older version, you just need to use find function to create a1 and a2, i.e.;
index = find(A(:,1)<0.3&A(:,2)>0.9);
a = A(index,:);
n = length(index);
  6 个评论
Joakim Karlsson
Joakim Karlsson 2018-9-13
It somewhat works but I can't get the "&" to work. So I want to do something like. a1 = got29(got29(:,5))>270 & got29(got29(:,5)<360,:);
So I find all rows that has between 270 and 360. But I gett error "Subscribt indices must either be real positive integers"
Aquatris
Aquatris 2018-9-13
编辑:Aquatris 2018-9-13
Try the find method;
index = find( got29(:,5)>270& got29(:,5)<360);
a = got29(index,:); % rows got29 that satisfy the 270-360 in 5th column
n = length(index); % number of rows that satisfy the relation

请先登录,再进行评论。

类别

Help CenterFile Exchange 中查找有关 Creating and Concatenating Matrices 的更多信息

产品


版本

R2017b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by