Comparing elements in one matrix in a loop
显示 更早的评论
Hi All,
I have a large matrix with one column containing only values. I want to make a loop and compare every time if the average of 2nd and 1st value is < than a predifined value. When the average of i and j value is > than the predifined value, to show as a result i and j. Thanks in advance!
采纳的回答
KALYAN ACHARJYA
2018-9-18
编辑：KALYAN ACHARJYA
2018-9-18
A=randi(30,20,1); %Random Matrix for Example
th=12; %Some Predefined value
[rows colm]=size(A);
for i=1:rows-1
c=(A(i,1)+A(i+1,1))/2;
if c > th
fprintf('The i is: %d and the next row i+1 value is: %d \n',i,i+1);
break;
end
end
6 个评论
KALYAN ACHARJYA
2018-9-18
The matrix you said having 1 column, so j value always 1.
KALYAN ACHARJYA
2018-9-18
编辑：KALYAN ACHARJYA
2018-9-18
What are i and j, as you are assuming?
KALYAN ACHARJYA
2018-9-18
编辑：KALYAN ACHARJYA
2018-9-18
Next position is i+1, why j?
Array having length, matrix has size, confirm?
Check my answer, it works as per your defined question (matrix case).
Anyway I am ready to help if I can
KALYAN ACHARJYA
2018-9-18
In My Example A is 20x1 Double, check the following-
KALYAN ACHARJYA
2018-9-18
编辑：KALYAN ACHARJYA
2018-9-18
Check I have edited the answer. You want to find all positions or the first one only? Like the following?
KALYAN ACHARJYA
2018-9-18
编辑：KALYAN ACHARJYA
2018-9-18
The first one only case. I have edited the answer, the added break statement. Please check.
Other c condition also possible, can you clarify more.
更多回答（0 个）
类别
在 帮助中心 和 File Exchange 中查找有关 Loops and Conditional Statements 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!
Translated by 
