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Comparing elements in one matrix in a loop

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Ancalagon8
Ancalagon8 2018-9-18
编辑： Ancalagon8 2018-9-18
Hi All,
I have a large matrix with one column containing only values. I want to make a loop and compare every time if the average of 2nd and 1st value is < than a predifined value. When the average of i and j value is > than the predifined value, to show as a result i and j. Thanks in advance!

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KALYAN ACHARJYA
KALYAN ACHARJYA 2018-9-18
编辑：KALYAN ACHARJYA 2018-9-18
A=randi(30,20,1); %Random Matrix for Example
th=12; %Some Predefined value
[rows colm]=size(A);
for i=1:rows-1
c=(A(i,1)+A(i+1,1))/2;
if c > th
fprintf('The i is: %d and the next row i+1 value is: %d \n',i,i+1);
break;
end
end
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KALYAN ACHARJYA
KALYAN ACHARJYA 2018-9-18
编辑：KALYAN ACHARJYA 2018-9-18
The first one only case. I have edited the answer, the added break statement. Please check.
Other c condition also possible, can you clarify more.
Ancalagon8
Ancalagon8 2018-9-18
编辑：Ancalagon8 2018-9-18
for example doing inside the loop the calculation to find c gives a 2-digit-result like
(11+10)/2= 10.5, ....... ,
....., (46+38)/2=42,
(468+46)/2=257 <-- so here break as the result has 3 digits

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