Hi Roy,
Tets this code and let me know if you need some help:
a = 4 ;y = 22.5; % Known values
xo = 1; % initial b val
fun = @(b) ( 12*pi^2*a^4 + 8*pi^2*a^2*b^2 + 12*pi^2*b^4 )/( 3*a^2*b^4 ) - y; % fun definition
fzero( fun,xo )
Here the solution:
b = 2.512065597813919
In a general case with 9 y values the code should be:
%%In case of 9 y values
a = 4 ;
y = [ 22.5 8 7 5 4 3 78 21 96 ];% Known values
for i = 1:length(y)
xo = 1;
fun = @(b) ( 12*pi^2*a^4 + 8*pi^2*a^2*b^2 + 12*pi^2*b^4 )/( 3*a^2*b^4 ) - y(i);
b(i)= fzero( fun,xo );
end
b
Command window response:
b =
2.512065597813919 3.650354401760769 3.880731223730568 4.671356482408150 5.534336598056011 8.191022687818798 1.752511072336621 2.567332724890523 1.656264772243542
