How to make inline function using for loop?
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I need to make following function using "function handle"....
x=[x(1),x(2),x(3),...…,x(N)]……..Let say N=50
for i=1:1:N
fun(i)=@(x) 2*a + b + 4*c*d + 6*e %a, b ,c , d and e are iterative variables
end
a=[x(1),x(6),x(11),x(16),x(21),x(26),....,x(46)]
b=[x(2),x(7),x(12),x(17),x(22),x(27),.....x(47)]
c=[x(3),x(8),x(13),x(18),x(23),x(28),.....x(48)]
d=[x(4),x(9),x(14),x(19),x(24),x(29),.....x(49)]
e=[x(5),x(10),x(15),x(20),x(25),x(30),.....x(50)]
How can I write function using for loop?
2 个评论
Walter Roberson
2018-9-22
Why are you storing the same calculated anonymous function N times?
Sajjad Malik
2018-9-22
采纳的回答
Walter Roberson
2018-9-22
fun = cell(N, 1);
F = @(x) 2*x(1:5:N) + x(2:5:N) + 4*x(3:5:N).*x(4:5:N) + 6*x(5:5:N);
fun(:) = {F};
Now fun stores N copies of the same function handle, each of which implements
@(x) 2*a + b + 4*c*d + 6*e
where a, b, c, d, e are short-hand for
a=[x(1),x(6),x(11),x(16),x(21),x(26),....,x(46)]
b=[x(2),x(7),x(12),x(17),x(22),x(27),.....x(47)]
c=[x(3),x(8),x(13),x(18),x(23),x(28),.....x(48)]
d=[x(4),x(9),x(14),x(19),x(24),x(29),.....x(49)]
e=[x(5),x(10),x(15),x(20),x(25),x(30),.....x(50)]
Each of the function handles will return a vector of length 50/5 = 10.
5 个评论
Sajjad Malik
2018-9-23
编辑：Sajjad Malik
2018-9-23
Walter Roberson
2018-9-23
You cannot use the function with fmincon because the objective function for fmincon needs to return a scalar.
Sajjad Malik
2018-9-23
Walter Roberson
2018-9-23
No. When your objective function returns a vector of results, then fmincon and most other minimizers are not appropriate. You would need something like gamultiobj() which tries to find pareto fronts.
Sajjad Malik
2018-9-23
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