How to write an integral using 'cumsum'?

6 次查看（过去 30 天）
NEELABJA CHATTERJEE
I want to write this discretized integral in MatLab using 'cumsum'.
I tried the following (where i0 = find(x==0))
Pp=Dx*cumsum(u(i0:end));
Pm=-Dx*[fliplr(cumsum(fliplr(u(1:i0-1)))) 0];
P=[Pm Pp];
Pk=0.5*(P(1:end-1)+P(2:end));
to compute $ \int_{-1}^{1} u(y,t) dy$ (for a fixed, to be evolved later time level; the integral from -1 to 1 of the function u(x,t)dx.) Now I want to compute [integral from 0 to x of the function u(y,t)dy] - [integral from 0 to 1 integral from 0 to y of the function u(z,t)dzdy] ~ I have attached the discretized form here with.
Any kind of help regarding this coding would be much appreciated.

请先登录，再回答此问题。

回答（0 个）

类别

在 Help Center 和 File Exchange 中查找有关 Numerical Integration and Differentiation 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by