how to calculate the convolution of two signal without using CONV() ?

287 次查看（过去 30 天）
Synchro_mdn
Synchro_mdn 2018-9-25
回答： Mehmet Eren Dikmen 2024-3-28
Hi everyone, i was wondering how to calculate the convolution of two sign without Conv();. I need to do that in order to show on a plot the process. i know that i must use a for loop and a sleep time, but i dont know what should be inside the loop, since function will come from a pop-up menu from two guides.(guide' code are just ready);
option = get(handles.popupmenu1,'value');
option2 = get(handles.popupmenu2,'value');
// something that switch the func.
conv(x,h);
//plot the conv.
  4 个评论
显示 2更早的评论
Image Analyst
Image Analyst 2018-9-25
Not sure what that means. Why do you need a delay? Do you want to show a set of boxes representing the kernel moving along over the top of another set of boxes representing the signal? Doing the convolution is one thing (a really easy thing), but providing the animation, if that is what is required will be a lot harder.
Synchro_mdn
Synchro_mdn 2018-9-25
Lets leave out that part, I just really need to know how to set the for loop for two different signal.

请先登录，再进行评论。

请先登录，再回答此问题。

采纳的回答

Dimitris Kalogiros
Dimitris Kalogiros 2018-9-25
close all
clearvars
%x=input('Enter x: ')
x=sin(2*pi*0.1.*(1:1:11));
%h=input('Enter h: ')
h=[1 2 3 4 5 3 1 -1];
% convolution
m=length(x);
n=length(h);
X=[x,zeros(1,n)];
H=[h,zeros(1,m)];
for i=1:n+m-1
Y(i)=0;
for j=1:m
if(i-j+1>0)
Y(i)=Y(i)+X(j)*H(i-j+1);
else
end
end
end
% plot results
figure;
subplot(3,1,1); stem(x, '-b^'); xlabel('n');
ylabel('x[n]'); grid on;
subplot(3,1,2); stem(h, '-ms');
xlabel('n'); ylabel('h[n]'); grid on;
subplot(3,1,3); stem(Y, '-ro');
ylabel('Y[n]'); xlabel('----->n'); grid on;
title('Convolution of Two Signals without conv function');
  3 个评论
显示 1更早的评论
Allard Quek
Allard Quek 2022-3-12
the first characters represent the colour and the second characters represent the shape:
'-b^': blue triangle
'-ro': red circle
'-ms': magenta square

请先登录，再进行评论。

更多回答（5 个）

Manoj Manu
Manoj Manu 2021-8-16
close all
clearvars
%x=input('Enter x: ')
x=sin(2*pi*0.1.*(1:1:11));
%h=input('Enter h: ')
h=[1 2 3 4 5 3 1 -1];
% convolution
m=length(x);
n=length(h);
X=[x,zeros(1,n)];
H=[h,zeros(1,m)];
for i=1:n+m-1
Y(i)=0;
for j=1:m
if(i-j+1>0)
Y(i)=Y(i)+X(j)*H(i-j+1);
else
end
end
end
% plot results
figure;
subplot(3,1,1); stem(x, '-b^'); xlabel('n');
ylabel('x[n]'); grid on;
subplot(3,1,2); stem(h, '-ms');
xlabel('n'); ylabel('h[n]'); grid on;
subplot(3,1,3); stem(Y, '-ro');
ylabel('Y[n]'); xlabel('----->n'); grid on;
title('Convolution of Two Signals without conv function');
Sk Group
Sk Group 2021-10-25
Convolution without Function in MATLAB
Convolution without conv function in MATLAB | Complete CODE | Explanation | Example And Output
For complete detailed post visit: https://www.swebllc.com/convolution-without-function-in-matlab/
Kiran K V
Kiran K V 2022-6-28

clear all;

clc;

x = input ('Enter the first signal/sequence ');

h = input('Enter the second signal/sequence ');

Find the length of the individual signals, and thus the output

[~,L]= size (x);

[~,M] = size (h);

len y = L + M - 1

y = zeros (1, len_y);

len = 1:1en_y;

for i = 0 / l * eny

for j = 0/1 * eny

if ((i-j+1)>0 && (i-j+1)<=M && (j+1)<=L) y(i+1)=y(i+1)+x(j+1),^ * h(i-j+1);

end

end

end

disp (y)

stem (len, y)

Muhammad
Muhammad 2023-8-27
1 2 3
-1 2 3
Mehmet Eren Dikmen
Mehmet Eren Dikmen 2024-3-28
Hi guys i need to find a matlab code which can take 2 inputs of 2 different signals and generates and y(t) signal. This y(t) signal must be a another signal. So I'm basicaly looking for a signal for output. This is soooo urgent

类别

在 Help Center 和 File Exchange 中查找有关 Filter Design 的更多信息

标签

产品


版本

R2017a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by