how to calculate the convolution of two signal without using CONV() ?

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Hi everyone, i was wondering how to calculate the convolution of two sign without Conv();. I need to do that in order to show on a plot the process. i know that i must use a for loop and a sleep time, but i dont know what should be inside the loop, since function will come from a pop-up menu from two guides.(guide' code are just ready);
option = get(handles.popupmenu1,'value');
option2 = get(handles.popupmenu2,'value');
// something that switch the func.
conv(x,h);
//plot the conv.
  4 个评论
Image Analyst
Image Analyst 2018-9-25
Not sure what that means. Why do you need a delay? Do you want to show a set of boxes representing the kernel moving along over the top of another set of boxes representing the signal? Doing the convolution is one thing (a really easy thing), but providing the animation, if that is what is required will be a lot harder.
Synchro_mdn
Synchro_mdn 2018-9-25
Lets leave out that part, I just really need to know how to set the for loop for two different signal.

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采纳的回答

Dimitris Kalogiros
Dimitris Kalogiros 2018-9-25
close all
clearvars
%x=input('Enter x: ')
x=sin(2*pi*0.1.*(1:1:11));
%h=input('Enter h: ')
h=[1 2 3 4 5 3 1 -1];
% convolution
m=length(x);
n=length(h);
X=[x,zeros(1,n)];
H=[h,zeros(1,m)];
for i=1:n+m-1
Y(i)=0;
for j=1:m
if(i-j+1>0)
Y(i)=Y(i)+X(j)*H(i-j+1);
else
end
end
end
% plot results
figure;
subplot(3,1,1); stem(x, '-b^'); xlabel('n');
ylabel('x[n]'); grid on;
subplot(3,1,2); stem(h, '-ms');
xlabel('n'); ylabel('h[n]'); grid on;
subplot(3,1,3); stem(Y, '-ro');
ylabel('Y[n]'); xlabel('----->n'); grid on;
title('Convolution of Two Signals without conv function');
  3 个评论
Allard Quek
Allard Quek 2022-3-12
the first characters represent the colour and the second characters represent the shape:
'-b^': blue triangle
'-ro': red circle
'-ms': magenta square

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更多回答(5 个)

Sk Group
Sk Group 2021-10-25
Convolution without conv function in MATLAB | Complete CODE | Explanation | Example And Output

Manoj Manu
Manoj Manu 2021-8-16
close all
clearvars
%x=input('Enter x: ')
x=sin(2*pi*0.1.*(1:1:11));
%h=input('Enter h: ')
h=[1 2 3 4 5 3 1 -1];
% convolution
m=length(x);
n=length(h);
X=[x,zeros(1,n)];
H=[h,zeros(1,m)];
for i=1:n+m-1
Y(i)=0;
for j=1:m
if(i-j+1>0)
Y(i)=Y(i)+X(j)*H(i-j+1);
else
end
end
end
% plot results
figure;
subplot(3,1,1); stem(x, '-b^'); xlabel('n');
ylabel('x[n]'); grid on;
subplot(3,1,2); stem(h, '-ms');
xlabel('n'); ylabel('h[n]'); grid on;
subplot(3,1,3); stem(Y, '-ro');
ylabel('Y[n]'); xlabel('----->n'); grid on;
title('Convolution of Two Signals without conv function');

Kiran K V
Kiran K V 2022-6-28

clear all;

clc;

x = input ('Enter the first signal/sequence ');

h = input('Enter the second signal/sequence ');

Find the length of the individual signals, and thus the output

[~,L]= size (x);

[~,M] = size (h);

len y = L + M - 1

y = zeros (1, len_y);

len = 1:1en_y;

for i = 0 / l * eny

for j = 0/1 * eny

if ((i-j+1)>0 && (i-j+1)<=M && (j+1)<=L) y(i+1)=y(i+1)+x(j+1),^ * h(i-j+1);

end

end

end

disp (y)

stem (len, y)


Muhammad
Muhammad 2023-8-27
1 2 3
-1 2 3

Mehmet Eren Dikmen
Mehmet Eren Dikmen 2024-3-28
Hi guys i need to find a matlab code which can take 2 inputs of 2 different signals and generates and y(t) signal. This y(t) signal must be a another signal. So I'm basicaly looking for a signal for output. This is soooo urgent

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