Outputs of a function

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Jaden
Jaden 2012-6-26
Hello! I'm currently writing functions that take input, and need to return a ouput to be used by a later function. However, in the function programming, I know that I have many different variables that I'm defining in order to do the function that I need. So when I try to get the function to do an output argument (i.e. X = function(input);), it gives me the error that I have too many output arguments.
Is there a way that I can label (inside the function itself) the one ouput I want so that it only sees that variable as the correct output?

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tlawren
tlawren 2012-6-26
Is your function declaration correct? For example, the following two functions are declared to return one and two variables respectively. Both take in three inputs.
function x = test1(a,b,c)
function [x,y] = test2(a,b,c)
If your function declaration looks like this
function test1(a,b,c)
and you try to get outputs from it with
x = test1(in1, in2, in3)
in your other code, then you will get a "Too many output arguments" error.
See the following for more details. http://www.mathworks.com/help/techdoc/ref/function.html

更多回答（1 个）

Jaden
Jaden 2012-6-26
Yeah, I don't think that I have the function declared right. However, the problem is that there are way too many "ouputs" in my program that I don't want used as outputs, but are simply used as parts of the transformations.
I'll paste some example code:
this is how I call the function:
function [dataValues] = transformingdata(fileName);
and this the function itself, where you can see that there are a lot of variables going on:
function transformingdata(laser)
%This function takes any polar laser data set and simply transforms it into Cartesian.
%% Determining height and width of transformed scan
[height, width] = size(laser);
%% Determine angles for xvalues
% Laser Radian Step Size == .00436
if(width == 720) xvalues = [95:-0.263541667:-94.75]; % FOR 190 DEGREES end
if(width == 1081) xvalues = [135:-0.2498169664173166:-135]; % FOR 270 DEGREES end
%% Transform degrees into radians
xvalues = ((xvalues*pi)/180);
%% Initialize values
numberOfScans = 1; dataPlot = []; plot2 = []; X = []; Y = []; plotY = []; plotX = [];
%% Transformation loop
while (numberOfScans < height)
[X, Y] = pol2cart(xvalues,laser(numberOfScans, :));
if (numberOfScans == 1)
Y = Y;
X = X;
end
if(numberOfScans > 1)
plotY = [plotY; Y];
plotX = [plotX; X];
end
plot2 = [];
plot2(:,:,1) = [plotY];
plot2(:,:,2) = [plotX];
numberOfScans = numberOfScans + 2;
end
%%New size
[he, wi] = size(plot2(:,:,1));
%%Initialize variables
numberOfScan = 1;
plot2(:,:,3) = zeros(he,wi);
%%Creating translation matricies
TX = [.09];
TY = [.25];
TZ = [-.22];
TX = TX*ones(1,wi);
TY = TY*ones(1,wi);
TZ = TZ*ones(1,wi);
%%Center of robot loop
while (numberOfScan < he)
dataPlot(numberOfScan,:,1) = plot2(numberOfScan,:,1) + TX;
dataPlot(numberOfScan,:,2) = plot2(numberOfScan,:,2) + TY;
dataPlot(numberOfScan,:,3) = plot2(numberOfScan,:,3) + TZ;
numberOfScan = numberOfScan + 1;
end
dataValues = dataPlot;
robot = 'done_data!'
end
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Walter Roberson
Walter Roberson 2012-6-26
Any variable whose name does not appear on the left side of the "function" statement (and which is not a global or nested variable) will be deleted when the function exit, so it is not a problem to create as many variables as you need to calculate the values that you want to return.

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