How would I write a script to solve this problem. Assume that I have a vector named D. Using iteration (for) and conditionals (if and/or switch), separate vector D into four vectors posEven, negEven, posOdd, and negOdd.

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Bryce Imbriale 2018-9-27

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https://ww2.mathworks.cn/matlabcentral/answers/421138-how-would-i-write-a-script-to-solve-this-problem-assume-that-i-have-a-vector-named-d-using-iterati

编辑： OCDER 2018-9-28

*Find the maximum, minimum elements and get the summation and so on, but how would I solve the problem using conditional statement and iterations instead.***

a. posEven contains all of the positive even numbers in D b. negEven contains all of the negative even numbers in D c. posOdd contains all of the positive odd numbers in D d. negOdd contains all of the negative odd numbers in D

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Bryce Imbriale 2018-9-28

编辑：Walter Roberson 2018-9-28

在 MATLAB Online 中打开

This is what i have so far but problebly looks super confusing.

>> D = [-4,-3,-2,-1,0,1,2,3,4]
posEven = []; posOdd = []; negEven = []; negOdd = [];
for val = D
    if val > 0
        if mod(val,2) == 0
            posEven = [posEven val]
        else
            posOdd = [posOdd val]
        end
    elseif val < 0
        if mod(val,2) == 0
            negEven = [negEven val]
        else
            negOdd = [negOdd val]
        end
    end
end
D =
Columns 1 through 8
    -4    -3    -2    -1     0     1     2     3
Column 9
     4
negEven =    -4    -2
negOdd =    -3    -1
posOdd =     1     3
posEven =     2     4

Walter Roberson 2018-9-28

What difficulty are you observing?

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Answer 1

OCDER 2018-9-28

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https://ww2.mathworks.cn/matlabcentral/answers/421138-how-would-i-write-a-script-to-solve-this-problem-assume-that-i-have-a-vector-named-d-using-iterati#answer_338797

编辑：OCDER 2018-9-28

在 MATLAB Online 中打开

My guess is Bryce needs to "find the maximum and minimum elements, and get the summation" for each variable. But seems max, min, or sum cannot be used.

Start with:

maxPosEven = posEven(1);
for j = 2:numel(posEven)
  if posEven(j) > maxPosEven  %Adjust the inner contents for your case
     maxPosEven = posEven(j);
  end
end