how we can store each and every value in nested for loop.

1 次查看（过去 30 天）
Sun Heat
Sun Heat 2018-10-5
编辑： KALYAN ACHARJYA 2018-10-5
d=linspace(2,4,3);
for t=1:length(d)
c(t)=d(t)^2;
PL=linspace(0.8,1,3);
for q=1:length(PL)
c1(q,t)=PL(q)^2;
N=linspace(11,13,3);
for y=1:length(N)
c2(y,q)=N(y)^2;
end
end
end

请先登录，再回答此问题。

采纳的回答

KSSV
KSSV 2018-10-5
d=linspace(2,4,3);
c = zeros([],[]) ;
c1 = zeros([],[]) ;
c2 = zeros([],[],[]) ;
for t=1:length(d)
c(t)=d(t)^2;
PL=linspace(0.8,1,3);
for q=1:length(PL)
c1(q,t)=PL(q)^2;
N=linspace(11,13,3);
for y=1:length(N)
c2(y,t,q)=N(y)^2;
end
end
end

更多回答（1 个）

KALYAN ACHARJYA
KALYAN ACHARJYA 2018-10-5
编辑：KALYAN ACHARJYA 2018-10-5
Here already value stored in each iteration
d=linspace(2,4,3);
PL=linspace(0.8,1,3);
N=linspace(11,13,3);
for t=1:length(d)
c(t)=d(t)^2;
for q=1:length(PL)
c1(q,t)=PL(q)^2;
for y=1:length(N)
c2(y,q)=N(y)^2;
end
end
end
Check result in command window: >> c
c =
4 9 16
>> c1
c1 =
0.6400 0.6400 0.6400
0.8100 0.8100 0.8100
1.0000 1.0000 1.0000
>> c2
c2 =
121 121 121
144 144 144
169 169 169
>>
  1 个评论
KALYAN ACHARJYA
KALYAN ACHARJYA 2018-10-5
编辑：KALYAN ACHARJYA 2018-10-5
For example
when t=1 c(1)=2^2=4
when t=2 c(2)=3^2=9
when t=3 c(3)=4^2=16
Please note you have used
linspace(2,4,3)
ans =
2 3 4

请先登录，再进行评论。

类别

在 Help Center 和 File Exchange 中查找有关 Introduction to Installation and Licensing 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by