How can I divide a linear array into 8 equal parts?

13 次查看（过去 30 天）
Zara Khan
Zara Khan 2018-10-8
评论： Kevin Chng 2018-10-11
A=[0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0]
This is a long linear array with consecutive 0's and 1's. How can I equally divide this array A into 8 equal parts and count no of 1's from each parts?
  5 个评论
显示 3更早的评论
Zara Khan
Zara Khan 2018-10-8
partSum(i) = sum(B(:,i))
this is always giving same values.
partSum =
0 5 10 0 0
partSum =
0 5 10 0 0
partSum =
0 5 10 0 0
partSum =
0 5 10 0 0
partSum =
0 5 10 0 0
I want to count only no of 1's from each of the 5 parts.
Kevin Chng
Kevin Chng 2018-10-8
编辑：Kevin Chng 2018-10-8
Just noticed the for-loop is not necessary.
B = reshape(A,[],5);
partSum = sum(B)
partSum =
0 5 10 0 0
0 is the total number of 1's in first part, 5 is the second part, 10........so on.
If want be more specific for better understanding, we could
first part = B(:,1);
second part = B(:,2);
third part = B(:,3);
fourth part = B(:,4);
fifth part = B(:,5);
then either use sum(first part) or nnz(firstpart) to count the number of 1's

请先登录，再进行评论。

请先登录，再回答此问题。

回答（2 个）

KSSV
KSSV 2018-10-8
You can get non zeros using nnz.
B = reshape(A,[],5)' ;
N = zeros(size(B,1),1) ;
for i = 1:size(B,1)
N(i) = nnz(B(i,:)) ;
end
  3 个评论
显示 1更早的评论
KSSV
KSSV 2018-10-8
I want to keep each of the part into linear as well. ?????example please.
Zara Khan
Zara Khan 2018-10-8
If I am diving a linear array into 8 equal parts then each 8 parts will be also linear. For example [0 0 1 1 0 1], [0 1 1 1 1 ] and so on.

请先登录，再进行评论。

Kevin Chng
Kevin Chng 2018-10-8
编辑：Kevin Chng 2018-10-9
How to count no of 1's from each parts ?
if let say we divide into 5 rows:
B = reshape(A,[],5);
partSum = sum(B);
you could nnz or sum.
What will be the code when the array size is not predefined?
A=[1 2 3; 4 5 6; 7 8 9]
numEle = numel(A);
for i=1:1:10
numberofsize = rem(numEle,i);
if numberofsize ~= 0
fprintf('array size is not correct for %i \n',i)
end
end
Then it will tell you what is the array size you can reshape them.
  7 个评论
显示 5更早的评论
Kevin Chng
Kevin Chng 2018-10-9
编辑：Kevin Chng 2018-10-9
Ya, you are right, it is my mistake.
NumEle is counting the number of element. Ya, you are right, i should use rem() instead. If the remainder is not 0, the size is not suitable for our reshape size.

请先登录，再进行评论。

类别

在 Help Center 和 File Exchange 中查找有关 Resizing and Reshaping Matrices 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by