How do I delete a row based on the based of the first column cell?

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For example. If I wanted to delete each row that contained the number 10 in the first column, how can I do that. Essentially is acts like a filter and deletes all the rows with that value.

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the cyclist
the cyclist 2012-6-28
If x is your array,
x(x(:,1)==10,:) = [];
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Brady Thom
Brady Thom 2012-6-28
编辑:Brady Thom 2012-6-28
Thank you for the speedy response! If you have a second, maybe a little description of what the notation does? I am just trying to learn and be more self sufficient
Ryan
Ryan 2012-6-28
编辑:Ryan 2012-6-28
x(:,1) == 10 returns a logical vector (1 for a 10, 0 otherwise). He's searching all rows (:,) and just the first column (,1).
x(logical vector,:) is locating the row's that have the 10 in the first column from before (dictated by the x(:,1) == 10) and saying select all the columns (,:) of those rows and then delete them by setting them equal to [].

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