importing xml and change to mat stuct

Question

KDRA 2018-10-10

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/423206-importing-xml-and-change-to-mat-stuct

评论： Daniel Abraham 2021-7-15

Hello,

I am trying to import multiple *.xml files from specific location and change them into mat structure files but I am facing some problems. This is my code:

if true
  % code
end
%loading files from device 
filedir= 'X:\GD\EA\ASP\Interest_groups\test\test_export.xml\pilot_studies'; %location of the files
file = dir(fullfile(filedir, '*.xml'));
mfiles=length(file); %number of files in the specified folder
for i = 1: mfiles
  fid(i)=fopen(fullfile(filedir, file(i).name),'rt');
  s{i}=textscan(fid(i), '%s', 'delimiter','\n');
  fclose(fid(i));
end
S = xml2struct(s)

It basically gives me the error in the last line saying that the first input to exist must be a string scalar or a character vector. My s variable is 1x3 cell which is weird. I am not sue how to solve it. I would appreciate your help.

K

1 个评论
显示 -1更早的评论隐藏 -1更早的评论

Raúl GB 2018-10-10

编辑：Raúl GB 2018-10-10

In the last line of the code written by you or the last line of code of any of the functions? Maybe by adding an example of how the xml looks like and the error message we may have a better idea.

请先登录，再进行评论。

请先登录，再回答此问题。

Answer 1

Guillaume 2018-10-10

0
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/423206-importing-xml-and-change-to-mat-stuct#answer_340671

在 MATLAB Online 中打开

You're making your life more complicated than you need to. You don't need to parse the file, xml2struct will do that for you, so the only thing you have to give it is the filename:

S = cell(1, numel(mfiles));
for i = 1 : mfiles
   S{i} = xml2struct(fullfile(filedir, file(i).name));   %load xml, convert to structure, and put structure in cell array
end
S = [S{:}];  %concatenate scalar structures into a structure array. Will fail if the xml of the files don't have the same elements.

xml2struct does not take a char array/string as input. The only other possible input is an xml DOM object as returned by xmlread:

S = cell(1, numel(mfiles));
for i = 1 : mfiles
   xml = xmlread(fullfile(filedir, file(i).name));  parse xml file
   S{i} = xml2struct(xml);   %convert xml to structure, and put structure in cell array
end
S = [S{:}];  %concatenate scalar structures into a structure array. Will fail if the xml of the files don't have the same elements.