Create a table with a generated polynomial

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Luis Paniagua 2018-10-11

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https://ww2.mathworks.cn/matlabcentral/answers/423407-create-a-table-with-a-generated-polynomial

评论： Image Analyst 2018-10-11

Hi there! I am using a code that generates and computes a polynomial, but I am now not interested in the result but in the form of the polynomial, therefore I would like to display each polynomial generated in a table having in each raw a polynomial. Hereby I let you the code.

 for j=1:200
 % calculate the n value
  n1 = (-1 + sqrt(1 + 8 * j)) / 2;
  n = floor(n1);
  if n1 == n
   n = n - 1;   
  end % if statement
% calculate the m value
k = (n+1)*(n+2)/2;
d = k - j;
m1 = n - 2*d;
m = abs(m1);
% calculate the sc value
sc = ' ';
if m1 > 0 
  sc = 's';
end % if statement
if m1 < 0 
  sc = 'c';
end % if statement
   Rnm = zeros(size(rho));
   for s=0:(n-m)/2
     numerator = (-1)^s * factorial(n-s);
     denominator = factorial(s)*factorial((n+m)/2-s)*factorial((n-m)/2-s);
     Rnm = Rnm + (numerator / denominator) * rho.^(n-2*s);  
   end % for s statement    
   % 3 cases.  sc=' ', 's', 'c'.
   theFactor = 1;
   switch sc
     case ' '
       % means m=0  
       theFactor = sqrt(n+1); 
       Zern_i(:, :, j) =theFactor* Rnm;  
     case 's'
       theFactor = sqrt(2*(n+1));  
       Zern_i(:, :, j) =theFactor* Rnm .* sin(m*theta);  
     case 'c'  
       theFactor = sqrt(2*(n+1));  
       Zern_i(:, :, j) =theFactor* Rnm .* cos(m*theta);  
   end 
end

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Luis Paniagua 2018-10-11

I want to have asingle column table that displays in each row the avobe generated polynomial, so the code generates 200 different polynomials, and I want a table with 200 rows, and in each one there must be a formula that shows how is the shape of the polynomial.

Image Analyst 2018-10-11

I don't see any table. You need to use the table() function, unless you simple want a matrix of doubles. To generate polynomial values, have you seen the polyval() function?

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