Function definition not supported in this context. Create functions in code file.
显示 更早的评论
Below is my code to solve the parallel plate capacitor problem.
clear all
x=linspace(1,20,10);
y=linspace(1,20,10);
[X,Y]=meshgrid(x,y);
C=delaunay(X(:),Y(:));
xy=[X(:) Y(:)];
Np=length(xy);
S=MatGlob(xy,C);
F=sparse(Np,1);
V0=1;
G=1e12;
for k=1:Np;
if x(k)==1
S(k,k)=S(k,k)+G;
F(k)=G*(-V0);
if x(k)==20
S(k,k)=S(k,k)+G;
F(k)=G*(+V0);
end
V=S\F;
figure
plot(xy,V,'*-')
title('potential(V)')
xlabel('postition(m)')
ylabel('postition(m)')
hold on
function S=MatGlob(xy,C)
Np=length(xy);
S=sparse(Np,Np);
Epsr=3.5;
Ne=size(C,1);
for k=1:Ne
N=C(k,:);
x1=xy(N(1),1);
x2=xy(N(2),1);
x3=xy(N(3),1);
y1=xy(N(1),2);
y2=xy(N(2),2);
y3=xy(N(3),2);
abc1=[1 x1 y1;1 x2 y2;1 x3 y3]\[1;0;0];
abc2=[1 x1 y1;1 x2 y2;1 x3 y3]\[0;1;0];
abc3=[1 x1 y1;1 x2 y2;1 x3 y3]\[0;0;1];
Grad=[abc1(2) abc2(2) abc3(2); abc1(3) abc2(3) abc3(3)];
Se=Epsr*(Grad'*Grad)*abs((x2-x1)*(y3-y1)-(x3-x1)*(y2-y1))/2;
S(N,N)=S(N,N)+Se;
end
end
Yet, Matlab annouce the error as follows: "Function definition not supported in this context. Create functions in code file" Would you please help me to fix this error? Thank you in advance.
5 个评论
Adam
2018-10-11
What version of Matlab are you using?
Simplest option is to do exactly what the error suggests though - create a new .m file, put the function in there and add it to your path.
@Duc Tu Vu: your code is badly aligned. Badly aligned code is one way that beginners hide bugs in their code, just like you have done. You should align your code using the default MATLAB Editor settings. You can also align existing code: select the code and press ctrl+i.
Mebo Valle
2021-12-8
I am experiencing the same problem, i have tried to align but nothing is happening, its just a simple and small code
function myRand
a=1+rand(3,4)*9
end
using R2019a
Mebo Valle
2021-12-8

Adam
2021-12-8
And you are getting the error about function definitions not being permitted in that context or some other problem?
采纳的回答
更多回答(1 个)
Duc Tu Vu
2018-10-11
0 个投票
5 个评论
WHISKY Chen
2019-3-23
How did you solve that problem? Could you please help me!
I have the same problem and... haven't solved it.
egg
2019-7-16
same here!
Steven Lord
2019-7-16
Try smart indenting your code to determine if you're trying to define a nested function inside an if, for, while, etc. statement (which is not allowed.)
Also make sure you're using release R2016b or later. The ability to define functions in scripts was introduced in release R2016b and will not work in earlier releases.
Naireeta Deb
2020-2-27
It doesn't work :/
Steven Lord
2020-2-27
Without more information about what you're doing (and ideally a small example with which you can reproduce the error) it's unlikely we'll be able to give you a more specific suggestion than what I did in my comment immediately before yours.
Make sure you're using release R2016b or later and make sure you're not trying to define the function inside an if, for, while, etc. statement (and you're not trying to define it by typing "function myoutput = ..." at the prompt in the Command Window.)
类别
在 帮助中心 和 File Exchange 中查找有关 Entering Commands 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!