assemble global stiffness matrix

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I am trying to assemble a matrix in which I would like to put small matrices into a big one but I don't know how to do that,
I know that I have to define the big matrix first and then show put the small ones inside
for example I have k1=[1 -1; -1 1] , K2=[1 -1; -1 1] and the define bigK in which bigK=zeros(3,3) and in the end I want it to be like bigK = [ 1 -1 0; -1 2 -1; 0 -1 1]
in which the small matrices will assemble in diagonal way
how I can do it using a for loop ?

采纳的回答

John D'Errico
John D'Errico 2018-10-12
K = zeros(10,10);
k = [1 -1; -1 1];
for n = 1:9;
rind = n + [0 1];
cind = rind;
K(rind, cind) = K(rind, cind) + k;
end
There are better ways to do this in terms of pure efficiency. But the above will suffice. First learn how to write at least decent code that solves the task at hand. Only when you decide if the code is a problem do you want to worry about optimizing it for speed.
  5 个评论
abdelrahman alhammadi
is there another way of doing it in a for loop in which I only define the small k function and size of big k and then it will do it by itself ?
Torsten
Torsten 2018-10-12
k=[1 -1; -1 1];
n=5;
K=zeros(n+1);
for i=1:n
K(i:i+1,i:i+1)=K(i:i+1,i:i+1)+k;
end
K

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更多回答(3 个)

Torsten
Torsten 2018-10-12
k1 = [1 -1; -1 1];
k2 = k1;
K = zeros(3,3)
K(1:2,1:2) = k1;
K(2:3,2:3) = K(2:3,2:3) + k2;
K

abdelrahman alhammadi
what if I have vector a1= [1; -1] and a2= [ 1 ;-1 ] and so on ... the big matrix F= [ 1; 0; 1] if the size was(2) how can I do that in a for loop ?
  2 个评论
John D'Errico
John D'Errico 2018-10-12
Please stop adding multiple answers for every single comment!
Beck Rinks
Beck Rinks 2022-7-25
Please only reply if you are giving answers. Thanks.

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Samba Dumbuya
Samba Dumbuya 2022-12-1
Hello,
I have computed the following stiffness matrix by hand;
[2/3 -1/6 -1/6 -1/3; -1/6 2/3 -1/3 -1/6;-1/6 -1/3 2/3 -1/6; -1/3 -1/6 -1/6 2/3]
Can someone please with codes that assemble the stiffness matrix into global matrix. The domain is discritize to square elemen.
thanks

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