Plot of the function after integration
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Hello. I want to plot a complicated function. Unfortunately at the end I obtain just one point of the function and the empty graph. I'd like to avoid exploitation of the command for to speed up my calculations. Could you explain where is my mistake? Thank you. Below is my code
function z=test_plot
tic
tt=-0.000689609;t=0.242731; muu=0.365908;
[m,NN]=meshgrid(0:100,-3000:1:3000);
y1= @(N,q,k) t*q./k.*log((-k.^2+2*k.*q-q.^2+muu+1i*(2*pi*N.*t-(2*m(1,:)+1)*pi*t))./(-k.^2-2*k.*q-...
q.^2+muu+1i*(2*pi*N.*t-(2*m(1,:)+1)*pi*t)))./(tt*pi+integral(@(a)a.*tanh((a.^2-muu)./(2*t)).*log((2*a.^2+2*a.*q+...
q.^2-2*muu-1i*2*pi*N*t)./(2*a.^2-2*a.*q+q.^2-2*muu-1i*2*pi*N*t))./q-2,0,10000,'AbsTol',1e-6,'RelTol',1e-3,'ArrayValued',true));
R1=@(q,k) integral(@(N)y1(N,q,k),3000,10^6,'AbsTol',1e-6,'RelTol',1e-3,'ArrayValued',true);
R11=@(q,k) integral(@(N)y1(N,q,k),-10^6,-3000,'AbsTol',1e-6,'RelTol',1e-3,'ArrayValued',true);
y2=@(q,k) t*q./k.*log((-k.^2+2*k.*q-q.^2+muu+1i*(2*pi*NN(:,1).*t-(2*m(1,:)+1)*pi*t))./(-k.^2-2*k.*q-...
q.^2+muu+1i*(2*pi*NN(:,1).*t-(2*m(1,:)+1)*pi*t)))./(tt*pi+integral(@(a)a.*tanh((a.^2-muu)./(2*t)).*log((2*a.^2+2*a.*q+...
q.^2-2*muu-1i*2*pi*NN(:,1).*t)./(2*a.^2-2*a.*q+q.^2-2*muu-1i*2*pi*NN(:,1).*t))./q-2,0,10000,'AbsTol',1e-6,'RelTol',1e-3,'ArrayValued',true));
R2=@(q,k) sum(y2(q,k));
S=@(q,k) R1(q,k)+R11(q,k)+R2(q,k)-4*sqrt(2)/pi*(1/1000)/(pi^(3/2)*sqrt(t))*q.^2;
Sigma=@(k) integral(@(q)S(q,k),0.001,7,'AbsTol',1e-6,'RelTol',1e-3,'ArrayValued',true);
Sum_sigma=@(k) 2*real(sum(Sigma(k)./((1i*(2*m(1,:)+1)*pi*t-k.^2+muu-Sigma(k)).*(1i*(2*m(1,:)+1)*pi*t-k.^2+muu))));
k=0.001:0.05:5.01;
Sum_sigma(k)
plot(k,Sum_sigma(k))
toc
end
12 个评论
Torsten
2018-10-12
Sum_Sigma(k) is a single value since you sum over Sigma(k).
Yuriy Yerin
2018-10-12
Yuriy Yerin
2018-10-12
Yuriy Yerin
2018-10-12
Torsten
2018-10-12
k = 0.001:0.05:5.01;
S = arrayfun(Sum_sigma,k);
plot(k,S)
Yuriy Yerin
2018-10-12
But it doesn't save time in comparison to the for-loop, does it ?
Maybe this could help to speed up your calculations:
Yuriy Yerin
2018-10-15
Torsten
2018-10-15
I have no experience with parallel computing in MATLAB. But since the calculations for different k-values are independent, it should somehow be possible to parallelize here.
Yuriy Yerin
2018-10-15
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