Why discrete transfer function show different result in Simulink but same result in Matlab?

Question

Archit Shah 2018-10-12

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/423720-why-discrete-transfer-function-show-different-result-in-simulink-but-same-result-in-matlab

编辑： Suyash Jadhav 2022-1-14

I am getting different results in Matlab & Simulink when I try to simulate step response of a discrete spring mass damper transfer function. Here is my transfer function.

H=tf([1],[1 0.2 1]); %transfer function of a continuous system
Hd=c2d(H,0.01)       %converting continuous system to a discrete system with sampling time of 0.01
Hd = 4.997e-05z +4.993e-05
    -----------------------
     z^2 - 1.998 z + 0.998
step(H,'-',Hd,'r--')

When I plot this in Matlab I get the same trajectory for both continuous and discrete system which is as expected .

Figure(1): Matlab result

The issue is when I try to do the same in Simulink, I get different result for the discrete system.

I made two changes to my Simulink settings in Model Configuration parameters:

1) I changed the solver selection from variable step to Fixed-Step

2) Fixed-Step size(Fundamental sample time) to 0.01. Everything else is kept as default

Figure(2): Simulink Model

-

Figure(3): Simulink Result

I don't understand what am I doing wrong in Simulink? I am expecting a trajectory similar to a continuous system

Thank you,

0 个评论
显示 -2更早的评论隐藏 -2更早的评论

请先登录，再进行评论。

请先登录，再回答此问题。

Answer 1

ONT 2020-5-12

3
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/423720-why-discrete-transfer-function-show-different-result-in-simulink-but-same-result-in-matlab#answer_432019

Hello,

The cause of this issue is that the discrete transfer function you have in Discrete Transfer Function Simulink block is not the same as the one that MATLAB calculated with c2d function.

The coefficents of Hd(z) after using c2d function on H(s) are:

for Numerator

0 4.99662669945566e-05 4.99329671410653e-05

for Denominator

1 -1.99790209943320 0.998001998667333

In your Simulink Discrete Transfer Function you rounded up the coefficents and therfore changed the dynamic behaviour of system.

If you retype the coefficents from MATLAB to Simulink exactly as they are, the step responses will align in Simulink just like in MATLAB. Same if instead of hand-typing the coefficents into Transfer Function block, you will use LTI System Block and reference H and Hd LTI objects from MATLAB workspace.