viewSolid is not working

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Ravi Prakash
Ravi Prakash 2018-10-14
评论： Steven Lord 2025-9-18，13:41
Its not working in my Matlab app.Its showing invalid function.What can i do

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回答（2 个）

Walter Roberson
Walter Roberson 2018-10-14
  2 个评论
Tansheed
Tansheed 2023-12-21
I did download it and moved it into the same file with the matlab files just as my lecturer instructed me to do. But it still shows invalid to me but in my peers comupters it succesfully executes the action
Tansheed
Tansheed 2023-12-21
Please tell us the possible reasons and how to slove them

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ATHUL N
ATHUL N 2025-9-18，13:31
Ran in:
clc;
clear all;
syms x y z
value = int(int(6*x*y, z, 0, 1 + x + y), y, 0, sqrt(x),x,0,1
Error using sym/int (line 128)
Too many arguments.
viewSolid(z,0,1+x+y,y,0*x,sqrt(x),x,0,1);
  1 个评论
Steven Lord
Steven Lord 2025-9-18，13:41
Ran in:
This line of code (commented out so I can run other commands later in the comment) is not syntactically valid, as it has three ( and two ). I assume you ran it and then deleted one of the closing parentheses. Where was that closing parenthesis? Was it at the end of the line?
%{
value = int(int(6*x*y, z, 0, 1 + x + y), y, 0, sqrt(x),x,0,1
%}
If it was, the inner call to int looks fine. [Since z doesn't appear in 6*x*y, you're integrating a constant.]
syms x y z
innerIntegral = int(6*x*y, z, 0, 1 + x + y)
innerIntegral = 
If you're trying to perform a triple integral, the innermost one over z, the middle one over y, and the outermost over x, you're missing two closing parentheses and an extra int( call.
middleIntegral = int(innerIntegral, y, 0, sqrt(x))
middleIntegral = 
outerIntegral = int(middleIntegral, x, 0, 1)
outerIntegral = 
Or putting them all together in one line:
% Added vvvv v v
value = int(int(int(6*x*y, z, 0, 1 + x + y), y, 0, sqrt(x)),x,0,1)
value = 

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