need help in matlab coding

How do I write coding for
x(i+1) = x(i) + 0.05(2*x(i) - t);
for i= 0:0.05:1
x(0) = 2.
For 1st iteration t = 0. For 2nd iteration t=0.05. For 3rd iteration t=0.1 and so on....
The answer will be: 2.2, 2.4175, 2.6542.......

3 个评论

i = 0:0.5:1 initial condition is x(0) = 2
Have you tried out any code?
Earlier question:
@Ali Asghar: remember to accept the answer that best helped to resolve your question.

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回答(1 个)

This works:
x(1) = 2;
t = 0:0.05:1
for k = 1 : length(t) - 1
x(k+1) = x(k) + 0.05 * (2 * x(k) - t(k));
end
% Show in command window:
x

2 个评论

thank you very much dear
I'm not sure if you will get any more answers after all this time, so do you want to go ahead and "Accept this answer"? Thanks in advance.

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提问:

2018-10-14

评论:

2018-10-16

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