Check an array of values if within an upper and lower limit

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Ayman Fathy
Ayman Fathy 2018-10-15
评论： Ayman Fathy 2018-10-15
I am trying to do the same thing as the following example but checking an array of numbers and not just x. However it is not working. can someone help?
x = 10;
minVal = 2;
maxVal = 6;
if (x >= minVal) && (x <= maxVal)
disp('Value within specified range.')
elseif (x > maxVal)
disp('Value exceeds maximum value.')
else
disp('Value is below minimum value.')
end

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采纳的回答

Dennis
Dennis 2018-10-15
If you want to operate on arrays you could do it like this:
x = 1:10;
minVal = 2;
maxVal = 6;
x(x(x<=maxVal)>=minVal)
disp('Values within specified range.')
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Dennis
Dennis 2018-10-15
x = [randi(10,19,1),randi(100,19,1)];
minVal = 2;
maxVal = 6;
x(:,3)=NaN;
idx=find(x(:,1)>=minVal&x(:,1)<=maxVal);
x(idx,3)=x(idx,2)

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更多回答（1 个）

KSSV
KSSV 2018-10-15
minVal = 2;
maxVal = 6;
if any(x >= minVal) && any(x <= maxVal)
disp('Value within specified range.')
elseif any(x > maxVal)
disp('Value exceeds maximum value.')
else
disp('Value is below minimum value.')
end
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显示 1更早的评论
Ayman Fathy
Ayman Fathy 2018-10-15
Lowerlimit = 1000; Upperlimit = 2000;
if any(s(:,1) >= Lowerlimit) && any(s(:,1) <= Upperlimit) s(:,3) = s(:,2); else s(:,3) = NaN; end
%Itried this code but didnt work
Ayman Fathy
Ayman Fathy 2018-10-15
this was my code previously and again didnt work:
% for x = size(s, 1) % % if (s(x, 1) >=Lowerlimit) (s(x,1) <= Upperlimit) % s(x, 3) = s(x, 2); % else % s(x, 2) = NaN; % end % end

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