3-D surface plot for vectors x1,y1,z1,x2,y2,z2..........xn,yn,zn

4 次查看（过去 30 天）

Amit 2012-6-30

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/42441-3-d-surface-plot-for-vectors-x1-y1-z1-x2-y2-z2-xn-yn-zn

I want to plot the vectors in 3 D surface.

I used plot3(x1,y1,z1,x2,y2,z2......xn,yn,zn) but I am getting lines in 3-D.

Can you please tell me how to plot like surface in 3 dimension for n vectors for 3 axes, i.e. x1,y1,z1,x2,y2,z2............xn,yn,zn.

Thanks.

0 个评论
显示 -2更早的评论隐藏 -2更早的评论

请先登录，再进行评论。

请先登录，再回答此问题。

采纳的回答

Walter Roberson 2012-6-30

0
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/42441-3-d-surface-plot-for-vectors-x1-y1-z1-x2-y2-z2-xn-yn-zn#answer_52226

Plot a surface in 3 dimension for n vectors? Probably not. In general, the choice of surface would be ambiguous and thus arbitrary. The situation is not much different from the problem of constructing a surface from a point-cloud.

For example, let x1, y1 be a circle, and let x2, y2 be a circle in a parallel plane, "aligned" (i.e., the line connecting the centers of the two circles is normal to both planes.) What is the surface? Is it a cylinder? Maybe. But maybe the actual surface is two cones joined at the point half way between the two centers. Can you prove otherwise just given the vectors?

6 个评论
显示 4更早的评论隐藏 4更早的评论

Amit 2012-6-30

Sorry,but I tried to findout how to do with so many vetors in help, but I mnot getting how to construct the representation of the triangles that tirmesh() requires for its input

Walter Roberson 2012-6-30

编辑：Walter Roberson 2012-7-1

在 MATLAB Online 中打开

X = [x1(:); x2(:); x3(:); x4(:); ...; xn(:)];
Y = [y1(:); y2(:); y3(:); y4(:); ...; yn(:)];
Z = [z1(:); z2(:); z3(:); z4(:); ...; zn(:)];
NV = n;  %number of vectors
VL = length(x1);
V = (1:((NV-1)*VL)-1).';
T1 = [V, V+1, V+VL];

Now, T1 will be a partial "tri" matrix built up like

|\|\|\
 - - -

Except that T1 is a bit too large: it has the entries that correspond to using the top point in each vector as the lower-left corner and the bottom point in the next vector as if it were the upper-left corner. These entries must be removed from T1, which can be done by removing each (VL+1)'st row.

After that you need to construct T2, in very much the same pattern, except being the upper-right triangles, like