creating a repeated matrix 2
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Hi all,
I have
k1x=repmat(h(19,1), [3,1]) ;
k2x=repmat(h(37,1), [3,1]) ;
k3x=repmat(h(55,1), [3,1]) ;
k4x=repmat(h(73,1), [3,1]) ;
k5x=repmat(h(91,1), [3,1]) ;
kxtotal= [k1x; k2x;k3x;k4x;k5x];
h is a column of numnbers As you can see
37=19+18
55=37+18
73=55+18.
So I add the number 18 to obtain the sequence 19, 37, 55, 73 ...
Is there a better or clever way to construct kxtotal.
To be honest Isakson, I would prefer (as you did in my previous question) something like
ixs = repmat( [1:6], [3,1] );
ktotal = arrayfun( @(ii) sprintf('S%u',ii), ixs(:), 'uni', false );
that is, the approach without the loop.
thanks
7 个评论
per isakson
2012-7-2
编辑：per isakson
2012-7-2
In my checklist for good code "Easy to read and understand" is one of the top items. I find the for-loop variant of my previous answer easier to understand.
If the performance of the for-loop is not good enough I search for another solution.
Sabbas
2012-7-2
per isakson
2012-7-2
"h(19,1)" that is not the 19:th value of a column vector?
per isakson
2012-7-2
How do I get the vector, h?
Sabbas
2012-7-2
采纳的回答
per isakson
2012-7-2
编辑：per isakson
2012-7-2
Try this
ktotal = repmat( transpose( h([19:18:19+4*18]) ), [3,1] );
ktotal = ktotal(:);
I use "transpose" instead of the blip, "'", because the latter is too easy to miss.
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