A the surface x->-10:10, y->-10:10, z=0 to a plot of a curve in 3d (using plot3 in Matlab 2014b)?

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Erez 2018-10-21

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评论： Star Strider 2018-10-21

I have a curve in 3-dimensions, corresponding to

     xx=0:9; yy=[-5:0 -1:-1:-4]; zz=[1:5 4:-1:0]; 
     plot3(xx,yy,zz,'-o');

I wish to plot a semi-transparent surface corrseponding to x->-10:10, y->-10:10, z=0

How do I add this to the plot? I use Matlab 2014b.

In addition, is there a way to plot such that the axes and their origin will show up in the middle of the figure, and not in the sides?

Thank you!

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jonas 2018-10-21

Please do not spam your question. If anything, it makes some people (like me) less inclined to help.

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Answer 1

Star Strider 2018-10-21

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此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/425173-a-the-surface-x-10-10-y-10-10-z-0-to-a-plot-of-a-curve-in-3d-using-plot3-in-matlab-2014b#answer_342486

在 MATLAB Online 中打开

Try this:

xx=0:9; 
yy=[-5:0 -1:-1:-4]; 
zz=[1:5 4:-1:0];
figure
plot3(xx,yy,zz,'-o');
hold on
patch([-10 10 10 -10], [10 10 -10 -10], 'r', 'FaceAlpha',0.2)
hold off
grid on

‘... is there a way to plot such that the axes and their origin will show up in the middle of the figure, and not in the sides?’

Not in R2014b. I believe that was added in R2017b.

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jonas 2018-10-21

编辑：jonas 2018-10-21

在 MATLAB Online 中打开

Just to add:

"In addition, is there a way to plot such that the axes and their origin will show up in the middle of the figure, and not in the sides?"

ax = gca;
ax.ZRuler.FirstCrossoverValue = 0;
ax.ZRuler.SecondCrossoverValue = 0;
ax.XRuler.FirstCrossoverValue = 0;
ax.XRuler.SecondCrossoverValue = 0;
ax.YRuler.FirstCrossoverValue = 0;
ax.YRuler.SecondCrossoverValue = 0;
box on