find cycle in array

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NA
NA 2018-10-22
编辑： Matt J 2020-6-5
I have a M M=[1,2 ;1,5; 2,4;2,5;4,5; 4,9;5,6;6,11;9,10;10,11] I want to find a loop in this array. I want this answer A={[1,2,5],[2,4,5],[4,5,6,9,10,11]}
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Sim
Sim 2019-10-9
编辑：Sim 2019-10-9
@Guillaume
Yes, thank you.. I tried what you suggested:
[1] Count all cycles in simple undirected graph version 1.2.0.0 (5.43 KB) by Jeff Howbert
[2] Count Loops in a Graph version 1.1.0.0 (167 KB) by Joseph Kirk
Unfortunately, both solutions [1] and [2] were not working for my case... but I understood more about the problem and the way to describe it! Thanks a lot, very helpful FileExchange submissions!
Just for information, the solution I was looking for was kindly provided by Matt J here:
https://ch.mathworks.com/matlabcentral/answers/483968-find-cycles-in-undirected-graph?s_tid=ab_old_mlc_ans_email_view#answer_395354
Can Chen
Can Chen 2020-6-5
Hi Na, I work at MathWorks on graphs. If you have a few minutes, I would very much appreciate hearing more about your workflow using cycles. Would you please contact me directly?

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Matt J
Matt J 2020-6-5
编辑：Matt J 2020-6-5
This can be done using the spatialgraph2D submission on the File Exchange,
https://www.mathworks.com/matlabcentral/fileexchange/73630-spatialgraph2d
M = [1,2 ;1,5; 2,4;2,5;4,5; 4,9;5,6;6,11;9,10;10,11]
G = graph(M(:, 1), M(:, 2));
hg=plot(G);
obj=spatialgraph2D(G,hg.XData,hg.YData);
[~,A]=obj.polyshape;
>> A{:}
ans =
1 5 2
ans =
2 5 4
ans =
4 5 6 11 10 9
>> obj.mosaic

更多回答（2 个）

KSSV
KSSV 2018-10-22
M=[1,2 ;1,5; 2,4;2,5;4,5; 4,9;5,6;6,11;9,10;10,11] ;
A={[1,2,5],[2,4,5],[4,5,6,9,10,11]} ;
[c,ia,ib] = unique(M(:,1)) ;
N = length(c) ;
B = cell(N,1) ;
for i = 1:length(c)
T = M(ib==i,:) ;
B{i} = unique(T(:)) ;
end
Guillaume
Guillaume 2018-10-22
There are no built-in algorithms in matlab to find cycles in graphs (undirected or directed). You'll either have to write your own, eg. using DFS or BFS (both DFS and BFS are implemented in matlab) or some other algorithm that you can find using your favorite search engine, or you'll have to use one of the submissions in the FileExchange ( [1], [2], and probably more)

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