Could anyone help me to get the sum of an array to a fixed value

2 次查看(过去 30 天)
A=[1 2 3 4;
5 6 7 8]
how to get the sum of A to be fixed to a
value of 20 such that all the values in A needs
to be changed according to it.
  3 个评论
jaah navi
jaah navi 2018-10-23
There is no fixed logic A=[1 2 3 4; 4 3 2 1] When I sum the above A it gives 20 the value in A needs to be changed such that the sum of A needs to be 20. the values in A can be negative,or it can be repeated more than once,twice,thrice and so on.

请先登录,再进行评论。

回答(3 个)

KSSV
KSSV 2018-10-23
A=[1 2 3 4;
5 6 7 8] ;
A = A(:) ;
iwant = cell([],1) ;
count = 0 ;
for i = 1:length(A)
B = nchoosek(A,i) ;
thesum = sum(B,2) ;
idx = thesum==20 ;
if any(idx)
count = count+1 ;
iwant{count} = B(idx,:) ;
end
end
iwant
  1 个评论
jaah navi
jaah navi 2018-10-23
What i actually need is the sum of A should be 20 and the values in A needs to be changed according to it,but when i run the above code it gives 36.could you please help me on this.

请先登录,再进行评论。


Bruno Luong
Bruno Luong 2018-10-23
"There is no fixed logic"
OK that's easy then
A(:) = 0;
A(1) = 20;
  3 个评论
jaah navi
jaah navi 2018-10-23
if i use the above command i am getting value only in the first place and the rest of the place is 0. But i need to have values in places where A already has values, provided no fixed logic is that the values of A can be changed .
Kevin Chng
Kevin Chng 2018-10-23
编辑:Kevin Chng 2018-10-23
How about
A(:)=1;
A(1) = 20-sum(A(2:end));
provided number of element in A lesser than 20.

请先登录,再进行评论。


Bruno Luong
Bruno Luong 2018-10-23
编辑:Bruno Luong 2018-10-23
Let's be more serious you can do many thing like shifting
A = A - sum(A) + 20/size(A,1);
or scaling
A = 20 * A ./ sum(A);
or both

类别

Help CenterFile Exchange 中查找有关 Characters and Strings 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by