how to formulate logical matrix in a loop?

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Shubham Mohan Tatpalliwar
评论： Andrei Bobrov 2018-10-25
i am having a matrix and want to separate them in the depending on its value
A=[1,2,3,4,5,6,7,8,9,10]
expected result are
idx1=[1,0,0,0,0,0,0,0,0,0] % for 1
...
idx10=[0,0,0,0,0,0,0,0,0,1] % for 10

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采纳的回答

Andrei Bobrov
Andrei Bobrov 2018-10-25
A = 1:10;
idx = A(:) == A(:)'
  2 个评论
Shubham Mohan Tatpalliwar
Shubham Mohan Tatpalliwar 2018-10-25
what should i change to have a 5 rows with a step of 2
Andrei Bobrov
Andrei Bobrov 2018-10-25
what should i change to have a 5 rows with a step of 2
?
A = 1:2:10;
idx = A(:) == A(:)';

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更多回答（1 个）

madhan ravi
madhan ravi 2018-10-24
编辑：madhan ravi 2018-10-24
A=[1,2,3,4,5,6,7,8,9,10]
RESULT = zeros(1,numel(A));
RESULT1= RESULT;
for i = 1:numel(A)
idx(i)=A(i)==1;
idx1(i)=A(i)==10;
end
RESULT(idx) = A(idx)
RESULT1(idx1) = A(idx1)
  10 个评论
显示 8更早的评论
madhan ravi
madhan ravi 2018-10-25
What should be the result after the loop?

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