No, because the number of elements of ((0.0011*(x(i):1*N)-x((i-1):N-1))) must always be N-1.
Objective function in a for loop
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hi all,
I have an objective function that I want to minimize
N=10
f=@(x) ((0.0011*(x(2:1*N)-x(1:N-1)))'*exp(-0.0078*x(4*N+1:4*N+N-1)))*3/20
is it possible to create a for loop so that the function changes for each i, like this?:
for i=2:10
f=@(x) ((0.0011*(x(i):1*N)-x((i-1):N-1)))'*exp(-0.0078*x(4*N+1:4*N+N-1)))*3/20
end
thanks
Nikolas
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