How can I make the vector output always a column vector?

5 次查看（过去 30 天）
Dinoma Degefa
Dinoma Degefa 2018-10-26
评论： Dinoma Degefa 2018-10-26
I'm having trouble with a problem where I need the output vector to be a column vector always. The output sometimes provided as row vectors and in the iteration stops as vector dimensions are not the same. The algorithm stops after sometime when the output takes row vector. Please help me how to fix the out of a vector always as a column vector. here is one example.
$x{n+1}=z{n}$ is not predictable. it gives sometimes as a row vector and sometimes as a column vector. it supposed to finish all 2000 iterations, but it will give me error sometimes
N=100;
matrixSize=N;
x{1}=fix(randi([5,5],N,1));
W=fix(randi([2,2],N,1));
for n=1:200;
y{n}=x{n}+W;
for j=1:N;
if y{n}(j,:)<0;
z{n}(j,:)=100;
else
z{n}(j,:)=99;
end
x{n+1}=z{n};
end
end
  1 个评论
Bruno Luong
Bruno Luong 2018-10-26
Your code has plenty of row vectors, and not column vectors.
a(j,:) % <- row
a(:,j) % <- column
Unless if you leave in a parallel universe than the rest of us.

请先登录，再进行评论。

请先登录，再回答此问题。

采纳的回答

madhan ravi
madhan ravi 2018-10-26
N=100;
matrixSize=N;
x{1}=fix(randi([5,5],N,1));
W=fix(randi([2,2],N,1));
for n=1:200;
y{n}=x{n}'+W;
for j=1:N;
if y{n}(j,:)<0;
z{n}(j,:)=100;
else
z{n}(j,:)=99;
end
x{n+1}=z{n};
end
end
  2 个评论
Dinoma Degefa
Dinoma Degefa 2018-10-26
Dear Sir, here is my code. but not working. after going a few iterations it will stop as the outcome for q4{n,:}=RR{n,:} is a row vector. run it reputedly you will see.
N=100;
matrixSize=N;
x{1,:}=fix(randi([50,50],N,1));
x{2,:}=fix(randi([200,200],N,1));
for n=2:2000;
beta(n)=(1/3)-(1/(n+2));
WWW{n,:}=beta(n)*x{n,:}-beta(n)*x{n-1,:};
WW1{n,:}=x{n,:}+WWW{n,:};
AA=eye(N);
y{n,:}=AA*x{n,:};
R{n,:}=AA*WW1{n,:};
for j=1:N;
if norm(R{n,:}(j,:))<1;
RR{n,:}(j,:)=R{n,:}(j,:);
else if norm(R{n,:}(j,:))<=2 & norm(R{n,:}(j,:))>=1;
if R{n,:}(j,:)<0;
RR{n,:}(j,:)=-1;
else if R{n,:}(j,:)>0;
RR{n,:}(j,:)=1;
else RR{n,:}(j,:)=0;
end
end
else if R{n,:}(j,:)-1<0;
RR{n,:}(:,j)=-1;
else if R{n,:}(j,:)-1>0;
RR{n,:}(j,:)=y{n,:}(j,:)-1;
else RR{n,:}(j,:)=0;
end
end
end
end
end
q4{n,:}=RR{n,:};
x{n+1,:}= y{n,:}-RR{n,:}; %(I-proxg2)Ax(n)
end
toc;

请先登录，再进行评论。

更多回答（0 个）

类别

在 Help Center 和 File Exchange 中查找有关 MATLAB 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by