plotting matrix verses vector
显示 更早的评论
Good evening
I want to plot a frequency vector (x-axes) with a path loss matrix which is 16*16
I tried this but it gives me an error
figure(1);
plot(p.f,H(1,:),
p.f,H(2,:),
p.f,H(3,:),
p.f,H(4,:),
p.f,H(5,:),
p.f,H(6,:),
p.f,H(7,:),
p.f,H(8,:),
p.f,H(9,:),
p.f,H(10,:),
p.f,H(11,:),
p.f,H(12,:),
p.f,H(13,:),
p.f,H(14,:),
p.f,H(15,:),
p.f,H(16,:));
3 个评论
Steven Lord
2018-10-26
What is the full text (everything displayed in red) of the error message?
What do the following commands show?
sf = size(p.f)
cf = class(p.f)
sh = size(H)
ch = class(H)
Stephen23
2018-10-26
You could just plot the whole matrix like this:
plot(p.f,H.')
Alice Faisal
2018-10-26
回答（2 个）
Star Strider
2018-10-26
The easiest solution is likely:
plot(p.f, H)
If ‘H’ is a square matrix, and you want to transpose it, use:
plot(p.f, H.')
instead.
2 个评论
Alice Faisal
2018-10-26
Star Strider
2018-10-26
I assumed ‘p.f’ is a vector.
If it a matrix the same size as ‘H’, either of my plot calls will work:
p.f = rand(16);
H = rand(16, 16);
figure
plot(p.f, H)
If not, you will have to choose what vector in ‘p.f’ to plot with. The vector must have 16 elements to plot with your (16x16) matrix.
madhan ravi
2018-10-26
编辑：madhan ravi
2018-10-26
An example its possible using loop:
H=rand(16)
p.f = 1:16
figure(1);
for i = 1:length(H)
plot(p.f(1,:),H(i,:))
hold on
end
类别
在 帮助中心 和 File Exchange 中查找有关 Mathematics 的更多信息
2018-10-26
2018-10-26
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!
Translated by 
