How can I create 3D pixels image

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Marcelo hernandez
Marcelo hernandez 2018-10-26
回答： Image Analyst 2018-10-30
I need to create a sphere in a box of 100 pixels per side
The code to form a circle is the following
imageSizeX = 100;
imageSizeY = 100;
[columnsInImage rowsInImage] = meshgrid(1:imageSizeX, 1:imageSizeY);
% Next create the circle in the image.
centerX = 50;
centerY = 50;
radius = 25;
circlePixels = (rowsInImage - centerY).^2 + (columnsInImage - centerX).^2 <= radius.^2;
% circlePixels is a 2D "logical" array.
% Now, display it.
image(circlePixels) ;
colormap([0 0 0; 1 1 1]);
imwrite(circlePixels,'circle.bmp');
How could the previous code be modified for a sphere?
  1 个评论
Rik
Rik 2018-10-26
Today I formatted your code, next time, use the {}Code button. See here for a GIF showing how to do it.

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回答（3 个）

Rik
Rik 2018-10-26
The code generating the binary mask is relatively easy to extend, but you'll have to think about the image format you want to save it in, and the way you want to show the 3D object in a Matlab figure.
imageSizeX = 100;
imageSizeY = 100;
imageSizeZ = 100;
[X,Y,Z] = ndgrid(1:imageSizeX, 1:imageSizeY, 1:imageSizeZ);
% Next create the circle in the image.
centerX = 50;
centerY = 50;
centerZ = 50;
radius = 25;
circlePixels = (Z-centerZ).^2 + (Y-centerY).^2 + (X-centerX).^2 <= radius.^2;
  7 个评论
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Rik
Rik 2018-10-27
If you want to superimpose them, why split them up in the first place? You can sum them (or calculate the mean, which save you from scaling the output).
I=mean(circlePixels,3);%converts to double as well
imshow(I)
imwrite(I,'sphere.bmp');
Rik
Rik 2018-10-30
Did this suggestion solve your problem? If so, please consider marking it as accepted answer. It will make it easier for other people with the same question to find an answer. If this didn't solve your question, please comment with what problems you are still having.

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tesarj13
tesarj13 2018-10-26
编辑：tesarj13 2018-10-26
imageSizeX = 100;
imageSizeY = 100;
imageSizeZ = 100;
[columnsInImage, rowsInImage,zInImage] =...
meshgrid(1:imageSizeX, 1:imageSizeY,1:imageSizeZ);
% Next create the circle in the image.
centerY = 50;
centerX = 50;
centerZ = 50;
radius = 25;
circlePixels = (rowsInImage - centerY).^2 + (columnsInImage - centerX).^2 +...
(zInImage - centerZ).^2 <= radius.^2;
% circlePixels is a 3D "logical" array. % Now, display it.
isosurface (circlePixels,1/2)
axis equal
Image Analyst
Image Analyst 2018-10-30
Try this:
[x,y,z] = sphere;
% Plot a sphere centered at the origin.
% Make radius 50
radius = 50;
x = radius * x;
y = radius * y;
z = radius * z;
surf(x,y,z)
grid on;
axis equal

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