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Can anyone explain this output of 1d conv() function?

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Ba Ba Black Sheep!
Ba Ba Black Sheep! 2018-10-27
评论： Bruno Luong 2018-10-27
>> u = [1 2 3];
>> v = [1 2 3];
>> w = conv(u, v)
w = 1 4 10 12 9
>>
Can anyone explain this output?
Question #1. How come two vectors of 3 elements generate 5 elements' output?
Question #2. How is the output being calculated?

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回答（1 个）

Stephan
Stephan 2018-10-27
编辑：Stephan 2018-10-27
Hi,
using:
conv([1,2,3],[1,2,3])
is the equivalent to multiply two polynomials:
(1*x^2 + 2*x + 3) * (1*x^2 + 2*x + 3)
If you simplify this (do the multiplication) you get:
1*x^4 + 4*x^3 + 10*x^2 + 12*x + 9
The coefficient matrix of this resulting polynomial is
[1 4 10 12 9]
which is the same as the result of
conv([1,2,3],[1,2,3])
See also the conv documentation for more detailed informations.
Best regards
Stephan

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