How to plot Fourier series with 100 terms ?

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Sakusan Puwanendran
Sakusan Puwanendran 2018-10-27
评论： Korosh Agha Mohammad Ghasemi 2020-9-22
I'm trying to plot the attached Fourier series for 100 terms but the plot shows values reaching 40 when I'm expecting maximum values to be around 4. This is what I've managed so far. I would appreciate if someone could help me understand where I'm going wrong
t=-pi:pi/10:pi;
vt=zeros(1,length(t));
for m=1:1:2;
bm=(8/m*pi)*(1-cos(m*pi/2))
vt= vt + bm*sin(m*t);
end
plot(t,vt)
  1 个评论
Korosh Agha Mohammad Ghasemi
Korosh Agha Mohammad Ghasemi 2020-9-22
clear all;clc;
syms x
pi=3.14;
sum=0;
y=exp(x); %function you want
a0=(1/pi)*int(y,x,-pi,pi);
for n=1:3
%finding the coefficients
an=(1/pi)*int(y*cos(n*x),x,-pi,pi);
bn=(1/pi)*int(y*sin(n*x),x,-pi,pi);
sum=sum+(an*cos(n*x)+bn*sin(n*x));
end
% https://www.instagram.com/koroshkorosh1/
ezplot(x,y,[-pi,pi]);
grid on;hold on;
ezplot(x,(sum+a0/2),[-pi,pi]);
% https://www.instagram.com/koroshkorosh1/

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采纳的回答

Bruno Luong
Bruno Luong 2018-10-27
编辑：Bruno Luong 2018-10-27
for m=1:1:2;
And you think this makes 100 terms??
Then
bm=(8/m*pi)*(1-cos(m*pi/2))
So you multiply by pi? Look like you need to concentrate on the parenthesis:
bm=8/(m*pi)*(1-cos(m*pi/2));
  1 个评论
Korosh Agha Mohammad Ghasemi
Korosh Agha Mohammad Ghasemi 2020-9-22
clear all;clc;
syms x
pi=3.14;
sum=0;
y=exp(x); %function you want
a0=(1/pi)*int(y,x,-pi,pi);
for n=1:3
%finding the coefficients
an=(1/pi)*int(y*cos(n*x),x,-pi,pi);
bn=(1/pi)*int(y*sin(n*x),x,-pi,pi);
sum=sum+(an*cos(n*x)+bn*sin(n*x));
end
% https://www.instagram.com/koroshkorosh1/
ezplot(x,y,[-pi,pi]);
grid on;hold on;
ezplot(x,(sum+a0/2),[-pi,pi]);
% https://www.instagram.com/koroshkorosh1/

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