does anyone know how to rewrite this into switch/case statements

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Pablo Garcia
Pablo Garcia 2018-10-30
编辑： John D'Errico 2018-10-30
n=input('Please enter a positive or negative integer: ');
if n < -2 || n > 5
disp(n/2)
else
if n <= 3
if n >= 0
disp(floor(n/2))
else
disp(ceil(n))
end
else
disp(1)
end
end
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John D'Errico
John D'Errico 2018-10-30
Yeah, I figured it was HW. Stupid stuff. Teacher makes you do silly things for no good reason. Grump. Rant. Grumble. ;-)
So, are you asking how to do different things, based on which range n falls in, using a switch/case?
Pablo Garcia
Pablo Garcia 2018-10-30
The homework is basically just asking us to switch the above code from an if/if-else statement to a switch/case statement that still keeps the same purpose. I understand how to use switch/case statements but I'm having trouble with the inequalities

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John D'Errico
John D'Errico 2018-10-30
The immediate answer is to look at histcounts. It will allow you to set up a series of break points, returning an integer that indicates which regime a number falls into. So it looks like the various cases you might care about are:
breaks = [-2 0 3 5]
Then the third output from histcounts will be an integer, depending on which interval a point falls in. The problem is, you have a special issue, in that histcounts tests to see if a point is in an interval if it is >= the breaks.
So histc would put 3 and 4 into the same bin! And it looks like you wants histcounts to do something different for n==3 versus n==4.
If you know that n is always an integer, that means you wanted to set the break points as
breaks = [-2 0 4 5];
Anyway, histcounts may be beyond the scope of this problem, since it has a simple resolution.
switch n
case {-1 -2}
% do whatever you might do when n==-1 or -2
case {0 1 2 3}
% do whatever you might do when n lives in this range
case {4 5}
% do whatever you might do when n lives in this range
otherwise
% we covered all the other cases, so this is what happens when n < -2 or > 5
disp(n/2)
end
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John D'Errico
John D'Errico 2018-10-30
编辑：John D'Errico 2018-10-30
That is exactly what otherwise does. It covers all cases that were not explicitly mentioned in the cases. The problem would be if you wanted to do something different for n<-2 compared to n>5. Then you would need to get trickier. For example, you might need to put an if inside the otherwise block.

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