清空筛选条件
清空筛选条件

Extract values within interquartile range in array

11 次查看（过去 30 天）
Vlatko Milic
Vlatko Milic 2018-10-31
评论： Sesilia Iileka 2019-3-6
Hi,
I want to extract values within an interquartile range in an array. Let say that the array looks as follows: v= [1 2 3 4 5 6 ......95 96 97 98 99]. The interquartile range is 25 and 75. How can I extract the array values from 25 to 75 to a new array? If possible, can I select other ranges than bottom and top 25%?
Thanks!

请先登录，再回答此问题。

采纳的回答

the cyclist
the cyclist 2018-10-31
编辑：the cyclist 2018-10-31
Use the quantile command to get whichever quantiles you want.
Then extract using logical indexing (as described on this documentation page).
v = 1:99;
q = quantile(v,[0.25 0.75])
v2 = v(v>q(1) & v<q(2))
  7 个评论
显示 5更早的评论
Vlatko Milic
Vlatko Milic 2018-10-31
I see, that sounds reasonable.Thank you for the pedagogic explanation :)
Sesilia Iileka
Sesilia Iileka 2019-3-6
Hi i want kind of the same thing but from a loop
like this:
for i = length(x)
xy = find(u==i | u>i & u4<(i+1)); #xy should find indices of u within that range i.e u(i)>=i<u(i+1)
N(i) = length(xy) #giving me counts of i
end
but then, the last iteration (last value of i) will be wrong by this expression.
how do i correct this please?
Thanks a lot

请先登录，再进行评论。

更多回答（1 个）

madhan ravi
madhan ravi 2018-10-31
编辑：madhan ravi 2018-10-31
v=1:100;
new_array = v(v >=25 & v<=75) %values between 25 to 75
new_array1 = v(v<25 | v>75) % values less than 25 and greater than 75
  6 个评论
显示 4更早的评论
Sesilia Iileka
Sesilia Iileka 2019-3-6
Hi i want kind of the same thing but from a loop
like this:
for i = length(x)
xy = find(u==i | u>i & u4<(i+1)); #xy should find indices of u within that range i.e u(i)>=i<u(i+1)
N(i) = length(xy) #giving me counts of i
end
but then, the last iteration (last value of i) will be wrong by this expression.
how do i correct this please?
Thanks a lot

请先登录，再进行评论。

类别

在 Help Center 和 File Exchange 中查找有关 Matrix Indexing 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by