Question about find function on matlab and
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I am trying to use the find function to locate the index where x = 4 is located but every time I see the value its 401 can someone please because i dont understand this at all.
回答（3 个）
Walter Roberson
2018-11-1
1 个投票
The output is correct.
The first x is 0. You increment by 0.01. So the N'th entry in x, x(N), contains (N-1)/100. Thus x(401) contains (401-1)/100 = 400/100 = 4.0. And that never changes.
madhan ravi
2018-11-1
编辑：madhan ravi
2018-11-1
x0 = 4 %edited after sir Walter’s comment
y0 = interp1(x,y_linear,x0)
Now you will get the corresponding y value when x is 4.
4 个评论
Walter Roberson
2018-11-1
y0 = 4
x0 = interp1(y_linear,x, y0)
madhan ravi
2018-11-1
Ah thank you sir Walter :).
Walter Roberson
2018-11-1
I suspect that the real question is to find x such that y is 4, which is what I coded for in my comment here.
madhan ravi
2018-11-1
find function to locate the index where x = 4
I am not sure either sir from the above statement
Eduardo Jimenez
2018-11-1
0 个投票
1 个评论
Walter Roberson
2018-11-2
Okay, then, always getting 401 is correct for the location of 4.0 . For x = 6, it would come out as 601.
The point of the exercise is to not have to come up with the formula, to use find() to locate the value.
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2018-11-1
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