Size mismatch using reshape in HDL Coder

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Alla 2018-11-2

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https://ww2.mathworks.cn/matlabcentral/answers/427592-size-mismatch-using-reshape-in-hdl-coder

评论： Bharath Venkataraman 2018-11-2

I have an 8x8 input matrix, since 2D matrices aren't supproted I reshape it to 64x1 for the input and then reshape it back within the function using A=reshape(A, 8, 8); it runs well in Matlab but the code generation spits out this error:

Size mismatch (size [64 x 1] ~= size [8 x 8]). The size to the left is the size of the left-hand side of the assignment.

What's odd is that the problem seems to have came out of nowhere because I'm almost certain It was working well and I didn't change anything then it just started to error.

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Answer 1

Bharath Venkataraman 2018-11-2

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Could you try assigning the value to a different variable rather than back to A. Ar = reshape(A,8,8);

use Ar in the code below.

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Alla 2018-11-2

Thank you, this seems to have solved the problem although I tired it earlier and it didn't.

If I may ask another question, something more basic, when I generate HDL code for a function that calls an other function, how does the generated code deal with that? does it include the called functions?

Bharath Venkataraman 2018-11-2