Trying to write conditional if loop for an interval

2018 11 2
2 个回答
更新时间：2018 11 2
3 次查看（30 天）

0 个投票

cellcount1 = 1.41e6;
cellcount2 = 1.54e6;
avgcellcount = (cellcount1 + cellcount2)./2;
upplimit = (0.05.*avgcellcount) + avgcellcount;
lowlimit = avgcellcount - (0.05.*avgcellcount);
a = [avgcellcount];
b = avgcellcount(avgcellcount > lowlimit & avgcellcount <upplimit);
if (lowlimit < avgcellcount) && (avgcellcount < upplimit)
disp(‘Cell Counts are within 10% limit’);
else
disp(‘Cell Counts are outside of 10% limit’);
end
keep getting this error: parse error:
syntax error
>>> disp(‘Cell Counts are within 10% limit’); ^
parse error:
syntax error
>>> else ^
parse error:
syntax error
>>> disp(‘Cell Counts are outside of 10% limit’); ^
parse error:
syntax error
>>> end

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回答（2 个）

madhan ravi
madhan ravi 2018-11-2

0 个投票

cellcount1 = 1.41e6;
cellcount2 = 1.54e6;
avgcellcount = (cellcount1 + cellcount2)./2;
upplimit = (0.05.*avgcellcount) + avgcellcount;
lowlimit = avgcellcount - (0.05.*avgcellcount);
a = [avgcellcount];
b = avgcellcount(avgcellcount > lowlimit & avgcellcount <upplimit);
if (lowlimit < avgcellcount) && (avgcellcount < upplimit)
disp('Cell Counts are within 10% limit');
else
disp('Cell Counts are outside of 10% limit');
end
Bruno Luong
Bruno Luong 2018-11-2
编辑：Bruno Luong 2018-11-2

0 个投票

This is not TeX or LaTeX
disp(‘Cell Counts are within 10% limit’);
MATLAB string quote is like this:
disp('Cell Counts are within 10% limit');

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