Sum through an array until a value is reached, then continue
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Assume you have 2 arrays x = linspace(0.001,0.005,1000); y = linspace(0,1,1000);
I want to start at the beginning of x, and sum consecutive columns until the sum = 0.1, then take the average of y across that range.... then continue doing this until the end of x
6 个评论
madhan ravi
2018-11-2
give a short example of your desired result
Bruno Luong
2018-11-2
Description inaccurate and contradictory.
It looks like the "cumulative sum" is actually y (100 elements).
x never reaches 0.1.
Cumulative sum on x and y never give 0.1 crossing at 100 elements.
Bruno Luong
2018-11-2
编辑：Bruno Luong
2018-11-2
"With the values given, the first 100 columns would sum to 0.1"
No body know where the 100 comes from. Anyone is guessing and people just wastes theirs times for you.
Not give example is better than give one that doesn't make sense.
Anthony
2018-11-2
采纳的回答
c=cumsum(x);
G=discretize(c, 0:0.1:c(end));
result = splitapply(@mean, y, G),
更多回答（2 个）
madhan ravi
2018-11-2
编辑：madhan ravi
2018-11-2
mean(y(cumsum(x)<=0.1))
8 个评论
Anthony
2018-11-2
madhan ravi
2018-11-2
see the edited answer
Anthony
2018-11-2
madhan ravi
2018-11-2
did you read Brunos comment?
Guillaume
2018-11-2
In case you haven't noticed you were given another answer that matches your description.
"this deosn't produce a correct output" is totally useless if you don't tell us what the correct output is. Vagues descriptions that don't actually match the example you've given doesn't cut it.
As has been pointed out, your statement "the first 100 columns would sum to 0.1" is incorrect. cumsum(x) reaches 0.1 at column 86.
Anthony
2018-11-2
Bruno Luong
2018-11-2
Yes 1 over 4 people figures it out ...by chance.
Anthony
2018-11-2
Guillaume
2018-11-2
sumx = cumsum(x);
meanybelowthreshold = mean(y(sumx <= 0.1));
meanyabovethreshold = mean(y(sumx > 0.1));
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