conv2 'valid' implementation
显示 更早的评论
I need to implement the conv2 function for a the HDL coder since it's not supported, I believe that I have the main function down, what I'm struggling with is the implementation of conv2 'valid' which is described in the documentation with — Returns only parts of the convolution that are computed without zero-padded edges-
The code for conv2 is the one I'm sharing, any help would be appreciated.
function B = convolve(A, k)
[r, c] = size(A);
[m, n] = size(k);
h = rot90(k, 2);
center = floor((size(h)+1)/2);
left = center(2) - 1;
right = n - center(2);
top = center(1) - 1;
bottom = m - center(1);
Rep = zeros(r + top + bottom, c + left + right);
for x = 1 + top : r + top
for y = 1 + left : c + left
Rep(x,y) = A(x - top, y - left);
end
end
B = zeros(r , c);
for x = 1 : r
for y = 1 : c
for i = 1 : m
for j = 1 : n
q = x - 1;
w = y -1;
B(x, y) = B(x, y) + (Rep(i + q, j + w) * h(i, j));
end
end
end
end
2 个评论
Juan Pereira
2019-10-7
Useful, thank you.
Savannah Quinn
2020-9-13
Hello, I am trying to use this code to implement various image filters however I keep getting the an index out of bounds error due to h(i,j). Any ideas?
采纳的回答
更多回答(2 个)
Bharath Venkataraman
2018-11-2
编辑:Bharath Venkataraman
2018-11-2
0 个投票
If you are looking for conv2 for image filtering, you can use the ImageFilter block and System object in Vision HDL Toolbox.
Bharath Venkataraman
2018-11-20
0 个投票
2 个评论
Alla
2018-11-29
Bharath Venkataraman
2018-11-29
conv2 with 'valid' returns a smaller image (without padding), so please make sure you are only comparing the central part of the image.
You may find it closer to matching if you use 'same' instead of 'valid'.
类别
在 帮助中心 和 File Exchange 中查找有关 Code Generation 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!