How can I flip a row vector without using flip(lr) function?

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denizakyol
denizakyol 2018-11-4
评论： Stephen23 2022-10-15
I want to write a function that it can flip a row vector without flip(lr) function.
if true
% A=[1 2 -3 4]
And output must be:
B=[4 -3 2 1]
end

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采纳的回答

Star Strider
Star Strider 2018-11-4
Reverse the indices:
A = [1 2 -3 4];
B = A(numel(A):-1:1)
B =
4 -3 2 1
  5 个评论
显示 3更早的评论
Star Strider
Star Strider 2018-11-4
@Image Analyst — Good point. Thank you.
I wanted to make my code straightforward, the reason I wrote it as I did. I was not certain if using end would do that.
denizakyol
denizakyol 2018-11-4
@Image Analyst Thank you so much. The end function is so helpful at all matrix operations. I would not forget anymore.

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更多回答（3 个）

Walter Roberson
Walter Roberson 2018-11-4
B = flipud(A.').';
madhan ravi
madhan ravi 2018-11-4
A=[1 2 -3 4]
B=wrev(A)
Saad
Saad 2022-10-15
how to conver a matrix without using (flip function's)?for example
a= 1 2 3 4 b=4 3 2 1
5 6 7 8 8 7 6 5
9 10 11 12 12 11 10 9
13 14 15 16 16 15 14 13
  2 个评论
Star Strider
Star Strider 2022-10-15
Ran in:
@Saad —
The same as I originally posted, with an additional row dimension —
a = [1:4; 5:8; 9:12; 13:16]
a = 4×4
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16
b = a(:,size(a,2):-1:1)
b = 4×4
4 3 2 1 8 7 6 5 12 11 10 9 16 15 14 13
.

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