How can I flip a row vector without using flip(lr) function?
显示 更早的评论
I want to write a function that it can flip a row vector without flip(lr) function.
if true
% A=[1 2 -3 4]
And output must be:
B=[4 -3 2 1]
end
采纳的回答
Star Strider
2018-11-4
Reverse the indices:
A = [1 2 -3 4];
B = A(numel(A):-1:1)
B =
4 -3 2 1
5 个评论
denizakyol
2018-11-4
Star Strider
2018-11-4
As always, my pleasure.
Image Analyst
2018-11-4
You can simply use "end" - you don't need to call the numel() function:
B = A(end:-1:1)
end still works inside the parentheses even though it's the first thing in there instead of the last.
Star Strider
2018-11-4
@Image Analyst — Good point. Thank you.
I wanted to make my code straightforward, the reason I wrote it as I did. I was not certain if using end would do that.
denizakyol
2018-11-4
更多回答（3 个）
Walter Roberson
2018-11-4
B = flipud(A.').';
Saad
2022-10-15
0 个投票
how to conver a matrix without using (flip function's)?for example
a= 1 2 3 4 b=4 3 2 1
5 6 7 8 8 7 6 5
9 10 11 12 12 11 10 9
13 14 15 16 16 15 14 13
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