more efficient way of coding a series of string variables which contain a fix subset of strings

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antonet 2012-7-5

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采纳的回答： Thomas

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Dear all,

I have the following list

l1= 'di _Aust.xlsx' ;

l2='di _Bel.xlsx' ;

l3='di_Est.xlsx';

 l4  = 'di_Fr.xlsx';
l5 = 'di_Ge.xlsx' ;
l6 = 'di_Gre.xlsx';
l7 = 'di_Ire.xlsx' ;
l8 = 'di_Ita.xlsx' ;
l9 = 'di_Nethe.xlsx';
   l10 ='di_Portu.xlsx' ;
   l11 ='di_Slova.xlsx' ;
   l12= 'di_Sloven.xlsx';
   l13= 'di_Spa.xlsx' ;

As you can see in any case the only part that changes is “di”. I was wondering if there is a more efficient way of writing this number of lists

For instance,

Kk={‘di’ ‘rt’ ‘ew’ }

And if I have, for example kk(2), then to get the output

l1= 'rt _Aust.xlsx' ;

l2='rt _Bel.xlsx' ;

l3='rt_Est.xlsx';

and so forth

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Answer 1

Thomas 2012-7-5

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IS this what you need?

kk={'di' 'rt' 'ew' };
name={'Aust' 'Bel' 'Est' 'Fr'};
for ii=1:length(name)
l=strcat(kk(1),'_',name(ii))
% xlswrite(l , data)   % here you have your xlswrite
end

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antonet 2012-7-5

thanks thomas!

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Answer 2

Mark Whirdy 2012-7-5

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Hi Looks like a case for regexp(), but for a more detailed solution I'll need you to reword your question as its difficult to understand exactly what variables you have and the code-behaviour you need.

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antonet 2012-7-5

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Hi. Thanks for your reply

What I have so far

l1= 'di _Aust.xlsx' ;

l2='di _Bel.xlsx' ;

l3='di_Est.xlsx';

l4 = 'di_Fr.xlsx';

xlswrite(l1 , data)

xlswrite(l2 , data)

xlswrite(l3 , data)

xlswrite(l4 , data)

What changes from this algorithm is the letters before the underscore bar inside the string variables l1 l2 l3; that is “di”. Each time I have to replace “di” with something else taken from a long list

list={‘di’, ‘sdrp’,…)

So I have to replace many times the “di” with something else taken from a long list and this process is boring. A more quick approach would cheer me up!

antonet 2012-7-5