Problem Valuing Multiple Swaps using the function 'swapbyzero'

1 次查看（过去 30 天）
Punar
Punar 2012-7-5
I have 1000 scenarios of interest rate term structres. Each scenario has various 'horizon dates' having a fixed interval between two consecutive dates. On each date I have 6 month forward LIBOR rates for 10 years.
Using these interest rates as an input, I need to value a swap with other inputs fixed on each of these dates. So, I would have 1000 swaps to be valued on each date - one corresponding to each scenario. On the next date only thing that changes is the valuation date.
To do this, I am using the function 'swapbyzero'.
The problem I am facing is that I am unable to value all the swaps in one go(calling the function just once).
s = 1 : NoOfScenarios;
i = 2 : NoOfHD;
Price = swapbyzero(RateSpec, LegRate, Settle, Maturity);
%RateSpec is the matrix of RateSpecs correponding to the horizon dates and the scenarios.
It says all the swaps should have same valuation date. Then I tried to value the 1000 swaps for each date in one go which have all inputs same except the interest rates.
s = 1 : NoOfScenarios;
for i = 2 : NoOfHD
Price(:,i) = swapbyzero(RateSpec(:,i), LegRate, Settle, Maturity);
end
When I do this, it gives the error: _The first argument must be 1 or 2 term structures created using INTENVSET._
Now I am left with only one option: to create two nested loops and value each swap individually - which takes around a minute for each scenario. It is 100x slower than the correpsonding Excel VBA code.
for s = 1 : NoOfScenarios
for i = 2 : NoOfHD
Price(:,i) = swapbyzero(RateSpec(:,i), LegRate, Settle, Maturity);
end
end
Probably I am not using the functions properly. Is there anyway else I can do it? Any other function to value the swaps or another way to use the function? Please help me out!
  2 个评论
Javier
Javier 2012-9-1
编辑：Jan 2012-9-1
Hello Punar
There is no need to do a loop. What you have to do is define the RateStructure with your 1000 interest rate structures. Procedure here:
1)Define Rate Structure
StartDate='01-Jan-2000';
EndDates=['02-Jan-2000';'03-Jan-2000';'06-Jan-2000';'10-Jan-2000' ...
;'01-Feb-2000';'01-Mar-2000';'01-Apr-2000';'01-May-2000';'01-Jun-2000';'01-Jul-2000' ...
;'01-Aug-2000';'01-Sep-2000';'01-Oct-2000';'01-Nov-2000';'01-Dec-2000';'01-Jan-2001' ...
;'01-Jan-2002';'01-Jan-2003';'01-Jan-2004';'01-Jan-2005'];
Rates=[0.0208;0.0208;0.0208;0.0209;0.0209;0.021;ones(10,1)*0.0215;0.0227;0.02441;0.02608;0.02764];
SimulRates=randn(20,1000)/1000;
SimulRates=SimulRates+Rates*ones(1,1000);
RateSpec=intenvset('Rates',SimulRates,'StartDates',StartDate,'EndDates',EndDates,'Compounding',1);
2)Swap Structure
settle = '01-Jan-2000';
Maturity = '01-Jan-2003';
Basis = 0;
Principal = [100;50;100]; %three notional amounts
LegRate = [0.06 20]; % [CouponRate Spread]
LegType = [1 0]; % [Fixed Float]
LegReset = [1 1]; % Payments once per year
3)Pricing
>> price = swapbyzero(RateSpec, LegRate, settle, Maturity, LegReset, Basis, Principal, LegType)
Hope it helps. Best Regards
Javier
[EDITED, Code formatted, Jan]
Jan
Jan 2012-9-1
@Javier, please post this as an answer, such that it can be accepted if it solved the problem. Thanks.

请先登录，再进行评论。

请先登录，再回答此问题。

回答（1 个）

Javier
Javier 2012-9-1
Hello Punar
There is no need to do a loop. What you have to do is define the RateStructure with your 1000 interest rate structures. Procedure here:
1)Define Rate Structure
StartDate='01-Jan-2000';
EndDates=['02-Jan-2000';'03-Jan-2000';'06-Jan-2000';'10-Jan-2000' ...
;'01-Feb-2000';'01-Mar-2000';'01-Apr-2000';'01-May-2000';'01-Jun-2000';'01-Jul-2000' ...
;'01-Aug-2000';'01-Sep-2000';'01-Oct-2000';'01-Nov-2000';'01-Dec-2000';'01-Jan-2001' ...
;'01-Jan-2002';'01-Jan-2003';'01-Jan-2004';'01-Jan-2005'];
Rates=[0.0208;0.0208;0.0208;0.0209;0.0209;0.021;ones(10,1)*0.0215;0.0227;0.02441;0.02608;0.02764];
SimulRates=randn(20,1000)/1000;
SimulRates=SimulRates+Rates*ones(1,1000);
RateSpec=intenvset('Rates',SimulRates,'StartDates',StartDate,'EndDates',EndDates,'Compounding',1);
2)Swap Structure
settle = '01-Jan-2000';
Maturity = '01-Jan-2003';
Basis = 0;
Principal = [100;50;100]; %three notional amounts
LegRate = [0.06 20]; % [CouponRate Spread]
LegType = [1 0]; % [Fixed Float]
LegReset = [1 1]; % Payments once per year
3)Pricing
price = swapbyzero(RateSpec, LegRate, settle, Maturity, LegReset, Basis, Principal, LegType)
Hope it helps. Best Regards
Javier

类别

在 Help Center 和 File Exchange 中查找有关 Price and Analyze Financial Instruments 的更多信息

标签

产品

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by