how can i create figures in a for loop
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I have to create a figure every 80 measurements of a row vector with length 31999 (Bn in the code). I tried to write this code but i receive only one figure with all the measurements (31999):
k= length(Bn);
for i= 1:80:(k-1)
Bn1(i) = L(i);
plot(Bn1);
end
any suggestion?
采纳的回答
Star Strider
2018-11-5
Try this:
repts = fix(numel(Bn)/80);
for k1 = 1:repts
figure(k1)
idxrng = (1:80) + 80*(k1-1);
plot(Bn(idxrng), L(idxrng))
grid
end
3 个评论
Elisa Mammoliti
2018-11-5
thank you Star Rider, it works and it gives what i need. Also really thank you to mahdan ravi for the support!!!
Star Strider
2018-11-5
My pleasure.
If my Answer helped you solve your problem, please Accept it!
Star Strider
2018-11-6
Something like this could work, creating a cell array of the findchangepts outputs:
repts = fix(numel(Bn)/80);
for k1 = 1:repts
figure(k1)
idxrng = (1:80) + 80*(k1-1);
ipt{k1} = findchangepts(L(idxrng));
plot(Bn(idxrng), L(idxrng))
grid
end
Note: The ‘ipt’ indices would be with respect to each section of ‘L(idxrng)’ not the entire ‘L’ vector. To create that, you would have to add the ‘80*(k1-1)’ offset to each set. If you want to do that, create a second set of vectors with those offsets, then concatenate them into one vector of serial ‘ipt’ values.
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