Convert loop to vectorization

2018 11 7
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更新时间：2018 11 7
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Here is simple code where I would like to remove for loop. A=[9;9;9]; c1=[2;3;5] for i=1:length(c1) c=c1(i,1); [B]=Subsum (A,c) i=i+1; end
Function subsum is defined as below
function [B] = Subsum (A,c) B=A-c; end
Desired output First loop B=[ 7 ;7;7] second loop B=[6;6;6] and Third loop B=[4;4;4]

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madhan ravi
madhan ravi 2018-11-7
编辑：madhan ravi 2018-11-7

1 个投票

A=[9;9;9];
c=[2;3;5];
b={(A-c)};
B=cell(1,length(c));
for i = 1:length(B)
B{i}=repmat(b{:}(i),numel(c),1);
end
celldisp(B)
command window
>> COMMUNITY
B{1} =
7
7
7
B{2} =
6
6
6
B{3} =
4
4
4
>>

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madhan ravi
madhan ravi 2018-11-7
what's your desired output?
Praveen
Praveen 2018-11-7
Thanks for the answer in case I want output as first loop B=[ 7 ;7;7] second loop B=[6;6;6] and Third loop B=[4;4;4]
Then code is A=[9;9;9]; c1=[2; 3; 5]; for i=1:length(c1) c=c1(i,1) [B] = Subsum (A,c) i=i+1; end
How can I write this without loop
Praveen
Praveen 2018-11-7
Your Answer was correct but I changed my question a bit
madhan ravi
madhan ravi 2018-11-7
if it was correct make sure to accept the answer

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