How to solve a nested summation with recursive function?

2 次查看(过去 30 天)
Hi,
I have a question related to solving a nested summation equation with a recursive function.
Suppose I have an equation of:
So, I tried to solve this problem by using a for loop to solve the summation equation and using a recursive function to expand the order of nested summation.
test(3,0)
function [sum] = test(a,b)
sum = 0;
for i=1:a-b
if a-b == 1
sum = 1;
else
sum = sum + (a-b) * test(a,b+i);
end
end
end
From the code I got
ans = 9
I appreciate any help, thanks.

采纳的回答

Matt J
Matt J 2018-11-7
编辑:Matt J 2018-11-7
I think your code is correct, and your calculation by hand is not.
  1 个评论
Irvanda Kurniadi Virdaus
编辑:Irvanda Kurniadi Virdaus 2018-11-7
Ah you are right, I think I messed up the break down on the second nested sum.
It should be:
3(2+0)+3(1)+3(0)=9
Thanks for correcting

请先登录,再进行评论。

更多回答(0 个)

类别

Help CenterFile Exchange 中查找有关 Matrix Indexing 的更多信息

产品


版本

R2017a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by