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How can I use an image as a 2 dimentional function?

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Nour Sd
Nour Sd 2018-11-8
编辑： Nour Sd 2018-11-8
Hello, I am trying to do Fast Fourier Transform function on an image which should be put on a 2 dimentional function, here's the fft function downloaded from MathWorks ,
function Y=ft2
size=length(input);
l=log2(size);
p=ceil(l);
Y=input;
N = 2^p;
N2=N/2;
YY = -pi*sqrt(-1)/N2;
WW = exp(YY);
JJ = 0 : N2-1;
W=WW.^JJ;
for L = 1 : p-1
u=Y(:,1:N2);
v=Y(:,N2+1:N);
t=u+v;
S=W.*(u-v);
Y=[t ; S];
U=W(:,1:2:N2);
W=[U ;U];
N=N2;
N2=N2/2;
end;
u=Y(:,1);
v=Y(:,2);
Y=[u+v;u-v];
Y
I want to apply this function on a grayscale image with the command
schimage = ft2(myimage,2);
But it doesn't work and the error is "Error using ft2 Too many input arguments."
Can anyone help me please?
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Nour Sd
Nour Sd 2018-11-8
I don't know how, can you please give me instructions?
Stephen23
Stephen23 2018-11-8
Your define the function ft2 to have zero input arguments:
function Y=ft2
and then try to call it with two input arguments. You should define the function with the correct number of input arguments that you require.

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KSSV
KSSV 2018-11-8
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KSSV
KSSV 2018-11-8
X = imread('peppers.png') ;
X = rgb2gray(X) ;
Y = fft2(X);
imagesc(abs(fftshift(Y)))
Nour Sd
Nour Sd 2018-11-8
编辑：Nour Sd 2018-11-8
Okay, I don't know if it gives a good result in my case but thank you anyway.

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